[img]http://img.photobucket.com/albums/v226/st2910/C12circuit.jpg[/img]
From the above circuit,
1) after the switch is closed for a long time, the capacitor is removed, is the ammeter reading affected? Why or why not?
2 after the switch is closed for a long time, the switch is opened. By recording the time when the pointer of the ammeter passes successive divisions of the scale and plotting a graph, I find that the half time of the decay is 36 seconds. However, theoratically, using the formula "Theoretical t1/2 = (ln 2) CR"(the equation is 100% correct), the half time calculated is 32.43 seconds. Why is there such an discrepancy?
Thank you for your help~