方程式請長列步驟,多謝合作
1. 2[a-(1-a)]=3(a-1)+8
2. 5m+3=9-4m
3. 2x=3(1-x)-(x+1)
4. k/30 +5=k/10
5. 9(2a-1)=3[4(1+2a)-5]-8a
6. 1/3(t+9)=1/3 -0.5(t+3)
7. (2n-5)/3=(n-10)/9
8. (x-1)/2 =(x+1)/3 +1
9. 7u -(4u-1)/2=21
10. (2-t)/4 -t=(2t-3)/5
11.Two trains are approaching each other from towns 600km apart.One train's speed is twice the other train's speed.They pass each other after 5 hours.Find their speeds.
In this problem,we note that :
distance=speed x time
first distance+second distance=total distance
Let the speed of the slower train be x km/h.
Then the speed of the other train=________.
In 5 hours,distance travelled by slower traim=------------ x ---------=----------km
Distance travelled by faster train=-----------x---------------=----------km
Given,total distance=-------------km
Therefore,-----+-----=------------
=
=
Therefore,the speeds of the trains are -------km/h and --------km/h