plz help me with this math problem 3ax+b=c.....solve for x?
回答 (13)
2009-08-05 2:43 pm
✔ 最佳答案
3ax + b = c3ax = c - b
x = (c - b)/3a
Answer: x = (c - b)/3a
Proof:
3a([c - b]/3a) + b = c
c - b + b = c
c = c
2016-09-30 5:28 pm
ok. nicely in accordance to the orders of operation- you should do exponents first. So 3 to the 2d potential is 9 and 3 to the 0.33 potential is 27. you have now 9+2 x 27. next, you should do multiplication. So 2 x 27 is fifty 4. you're actually left with 9+fifty 4 that's sixty 3!
2009-08-05 3:14 pm
3ax + b = c
3ax = c - b
x = (c - b)/(3a)
3ax = c - b
x = (c - b)/(3a)
2009-08-05 2:50 pm
3ax+b=c
3ax=c-b
3ax/3a=(c-b)/3a
x=(c-b)/3a
3ax=c-b
3ax/3a=(c-b)/3a
x=(c-b)/3a
2009-08-05 2:45 pm
3ax+b=c
3ax=c-b
.....c-b
x=------- answer//
......3a
3ax=c-b
.....c-b
x=------- answer//
......3a
2009-08-05 2:41 pm
hey its easy.....3ax+b=c=>3ax=c-b=>x=(c-b)/3a
2009-08-05 2:41 pm
3ax+b=c
3ax= -b+c
(3ax)/(3a)=(-b+c)*(1)/(3a)
x=(-b+c)*(1)/(3a)
x=(-b+c)/(3a)
3ax= -b+c
(3ax)/(3a)=(-b+c)*(1)/(3a)
x=(-b+c)*(1)/(3a)
x=(-b+c)/(3a)
2009-08-05 2:40 pm
3ax + b = c
subtract b from both sides
3ax = c - b
divide both sides by 3a
x = (c - b)/3a
subtract b from both sides
3ax = c - b
divide both sides by 3a
x = (c - b)/3a
2009-08-05 2:39 pm
Do it in two stages.
3ax = c - b
x = (c - b)/3a
3ax = c - b
x = (c - b)/3a
2009-08-05 2:39 pm
3ax + b = c
3ax = c - b
x = (c - b)/3a
3ax = c - b
x = (c - b)/3a
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