plz help me with this math problem 3ax+b=c.....solve for x?

3ax + b = c
3ax = c - b
x = (c - b)/3a

Answer: x = (c - b)/3a

Proof:
3a([c - b]/3a) + b = c
c - b + b = c
c = c

ok. nicely in accordance to the orders of operation- you should do exponents first. So 3 to the 2d potential is 9 and 3 to the 0.33 potential is 27. you have now 9+2 x 27. next, you should do multiplication. So 2 x 27 is fifty 4. you're actually left with 9+fifty 4 that's sixty 3!

3ax + b = c
3ax = c - b
x = (c - b)/(3a)

3ax+b=c
3ax=c-b
3ax/3a=(c-b)/3a
x=(c-b)/3a

3ax+b=c
3ax=c-b
.....c-b
x=------- answer//
......3a

hey its easy.....3ax+b=c=>3ax=c-b=>x=(c-b)/3a

3ax+b=c

3ax= -b+c

(3ax)/(3a)=(-b+c)*(1)/(3a)

x=(-b+c)*(1)/(3a)

x=(-b+c)/(3a)

3ax + b = c
subtract b from both sides
3ax = c - b
divide both sides by 3a
x = (c - b)/3a

Do it in two stages.

3ax = c - b

x = (c - b)/3a

3ax + b = c
3ax = c - b
x = (c - b)/3a