1.A room is 6 m long,5 m wide and 3 m high.If the total area of the door and windows is 4m2,find the total aera of the walls inside the room.
2.The cost of making a wardrobe is the sum of the following:
Wood...........$1385
Paint.............$617
Metal............$195
Labour..........$807
(a)Estimate the cost of making a wardrobe.
(b)If the the cost of wood is increased by 25% and the others remain unchanged,estimate the new cost of making a wardrobe.
f.1 maths
2009-08-05 8:03 pm
回答 (2)
2009-08-17 2:16 am
✔ 最佳答案
1.[(53)+(53)]+[(63)+(63)]-4
=(15+15)+(18+18)-4
=30+36-4
=62m2
∴The total aera of the walls inside the room is 62m2.
2a.
1385+617+195+807
=1400+600+200+800
=2000+1000
=3000
∴The cost of making a wardrobe is $3000.
2b.
(1385+52%)+617+195+807
=(1400+52%)+600+200+800
=1400+600+200+800
=2000+1000
=3000
∴The new cost of making a wardrobe is $3000.
2009-08-16 3:57 am
1)
6x5x2+6x3x2+3x5x2-4.2
=60+36+30-4.2
=126-4.2
=121.8
∴The total aera of the walls inside the room is 121.8m^2.
2a)
1385+617+195+807
=1400+600+200+800
=2000+1000
=3000
∴The cost of making a wardrobe is $3000.
2b)
1385x(1+25%)+617+195+807
=1400+1400x25%+600+200+800
=1400+350+600+200+800
=3000+350
=3350
∴The new cost of making a wardrobe is $3350.
6x5x2+6x3x2+3x5x2-4.2
=60+36+30-4.2
=126-4.2
=121.8
∴The total aera of the walls inside the room is 121.8m^2.
2a)
1385+617+195+807
=1400+600+200+800
=2000+1000
=3000
∴The cost of making a wardrobe is $3000.
2b)
1385x(1+25%)+617+195+807
=1400+1400x25%+600+200+800
=1400+350+600+200+800
=3000+350
=3350
∴The new cost of making a wardrobe is $3350.
參考: me`
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