How does (x√x + √x) simplify to √x(x + 1) ?

x√x + √x
= (√x)(x) + (√x)(1)
= (√x)(x + 1)

√x is a common factor hence :-

( x √x + √x ) = √x ( x + 1 )

GIVEN

(x√x + √x)

Factor out " √x "

and this becomes

√x (x + 1)

Hope this helps.

How does (x√x + √x) simplify to √x(x + 1)

'cos
√x(x + 1)
= √x * x + √x *1
= x√x + √x


QED

By the distributive property, which says that a * b + a * c = a(b + c) for any real numbers a, b, and c.

(x√x + √x) = (√x * x + √x * 1) = √x(x + 1).

take √x common =>√x(x+1)

√x is a factor of both x√x and √x, so we can factor it out the front. Removing the √x factor from x√x, we get x. Removing it from √x will leave us with 1. Hence we get √x (x + 1)

Look at it as: Ba + a

=> a( B + 1 )

Because you can divide both terms by root x