How does (x√x + √x) simplify to √x(x + 1) ?
回答 (9)
2009-07-29 4:42 pm
✔ 最佳答案
x√x + √x= (√x)(x) + (√x)(1)
= (√x)(x + 1)
2009-07-31 7:55 pm
âx is a common factor hence :-
( x âx + âx ) = âx ( x + 1 )
( x âx + âx ) = âx ( x + 1 )
2009-07-29 4:32 pm
GIVEN
(xâx + âx)
Factor out " âx "
and this becomes
âx (x + 1)
Hope this helps.
(xâx + âx)
Factor out " âx "
and this becomes
âx (x + 1)
Hope this helps.
2009-07-29 4:31 pm
How does (xâx + âx) simplify to âx(x + 1)
'cos
âx(x + 1)
= âx * x + âx *1
= xâx + âx
QED
'cos
âx(x + 1)
= âx * x + âx *1
= xâx + âx
QED
2009-07-29 4:30 pm
By the distributive property, which says that a * b + a * c = a(b + c) for any real numbers a, b, and c.
(xâx + âx) = (âx * x + âx * 1) = âx(x + 1).
(xâx + âx) = (âx * x + âx * 1) = âx(x + 1).
2009-07-29 4:30 pm
take âx common =>âx(x+1)
2009-07-29 4:30 pm
âx is a factor of both xâx and âx, so we can factor it out the front. Removing the âx factor from xâx, we get x. Removing it from âx will leave us with 1. Hence we get âx (x + 1)
2009-07-29 4:30 pm
Look at it as: Ba + a
=> a( B + 1 )
=> a( B + 1 )
2009-07-29 4:27 pm
Because you can divide both terms by root x
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