When 16b2 + 10b - 21 is factored, one factor is:?

16b² + 10b - 21 = 0
b² + 5/8b = 21/16
b² + 5/16b = 21/16 + (5/16)²
b² + 5/16b = 336/256 + 25/256
(b + 5/16)² = 361/256
b + 5/16 = ± 19/16

= b + 5/16 - 19/16, = b - 14/16, = b - 7/8, = 8b - 7
= b + 5/16 + 19/16, = b + 24/16, = b + 3/2, = 2b + 3

Answer: e) none of those—(8b - 7)(2b + 3) are the factors.

( 8 b - 7 ) ( 2 b + 3 )

OPTION e)

16b^2 + 10b - 21
= 16b^2 + 24b - 14b - 21
= (16b^2 + 24b) - (14b + 21)
= 8b(2b + 3) - 7(2b + 3)
= (2b + 3)(8b - 7)
(answer e)

16b2 + 10b - 21
=16b2+24b-14b-21
=8b(2b+3)-7(2b+3)
=(8b-7)(2b+3)

so none of these

e....
the factors are (8b-7)(2b+3)..

Factor 16b² + 10b - 21

( 8b - 7 )( 2b + 3 )

ANSWER: e) none of these

16b^2+10b-21=(factor 1)(factor 2)

so factor 1, and factor 2 should satisfy this equation,

16b^2+10b-21=0

but neither of the four options satisfy this equation......

so answer is "e"

E. The factors are (2b+3) & (8b-7)

16b^2+10b-21=(8b-7)(2b+3)
.
.
.
E) None of these.

d