✔ 最佳答案
Use "Applied Maths - Mechanics 4" as reference, the centre of mass of a Cone + Hemisphere is located at (3r2 – h2)/[4(h + 2r)] where density A = density B, and the direction towards the hemisphere is taken as positive.
Refer to the diagram, as far as the centre of mass does not go beyond u into the hemisphere, the solid can rest of the cone surface.
http://img89.imageshack.us/img89/6367/icecreamx.jpg
Now tan x = r/h = u/r so u = r2/h.
Compute u - (3r2 – h2)/[4(h + 2r)]
= r2/h - (3r2 – h2)/[4(h + 2r)] = (8r3 + hr2 + h3) / [4h(h + 2r)] > 0
Hence the centre of mass does not go beyond u and so the cone can rest on the cone surface on a horizontal plane.