factor completly b^2-21b-100 answer should look like this(b )(b ) what are the missing numbers can someone p?
回答 (4)
2009-07-26 5:23 pm
✔ 最佳答案
b^2 - 21b - 100= b^2 + 4b - 25b - 100
= (b^2 + 4b) - (25b + 100)
= b(b + 4) - 25(b + 4)
= (b + 4)(b - 25)
2009-07-26 11:48 pm
(b+4)(b-25)
2009-07-26 11:47 pm
(b-25)(b+4)
2009-07-26 11:52 pm
b^2-21b-100
This is the expression and the factorisation is required
So,
b^2 - 21b - 100
= b^2 - 25b + 4b - 100
= b * (b - 25) + 4 * (b - 25)
= (b + 4) * (b - 25)........................(Ans)
Hope this will help u
This is the expression and the factorisation is required
So,
b^2 - 21b - 100
= b^2 - 25b + 4b - 100
= b * (b - 25) + 4 * (b - 25)
= (b + 4) * (b - 25)........................(Ans)
Hope this will help u
收錄日期: 2021-05-01 12:46:02
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090726084313AAB7oWm