數學問題a_a

2009-07-27 4:04 am
1.有向數

(a) (-8)+(-5)=____ (b) (+9)+(-2)=____

(c) (+7)-(+12)=____ (d) (-5)-(-6)=____

(e) (+5)+(-7)+(-10)=____ (f) (-6)-(-8)+(+4)=____

(g) (-3)+(-4)-(-7)=____ (h) (+4)-(-9)+5)=____


2.有向數(二)

(a) (+2)(+7)=____ (b) (-3)(-9)=____

(c) (-10)(+7)=____ (d) (+5)(-3)=____

(e) (+2)(+13)(+4)=____ (f) (-3)(-7)(-9)=____

(g) (-3)(+12)(-5)=____ (h) (+4)(+17)(-3)=____


3.有向數(三)

(a) (+144)÷(+12)=____ (b) (-81)÷(-9)=____

(c) (-169)÷(+13)=____ (d) (+196)÷(-14)=____

(-8)×(+1.75) (-2.8)×(-4)
(e) ---------------- =____ (f) ---------------=____
(-5) (-7)

1 1 1 -1
(g) 3-- - ( +2-- - --- ) ÷ --- = _____
4 2 -2 4

5 -22 5 -9
(h) ( + -- ) ( ------ ) - ( -- ) ( --- ) = _____
7 15 6 20


有向數 (應用題) [算式+答案]

1.早上氣溫為-3度,午間氣溫上升了10度,晚間下降了12度,
求晚間的氣溫。

3 3 7 7
2.計算 ( - -- ) × ( - -- ) × ( - -- ) ÷ ( - --- ) 。
4 4 8 16

3.某人站於水平面上10m,而海則深26m,問該人與海底的垂
直距離為多少?

ab+bc-2ac ab
4.若 a=+3、b=-3,且 c=-5,則 --------------- - --- 的值是多少?
+5-(-6)+a c

回答 (2)

2009-07-27 4:58 am
✔ 最佳答案
1.有向數

(a) (-8)+(-5)=-13 (b) (+9)+(-2)=7

(c) (+7)-(+12)=-5 (d) (-5)-(-6)=1

(e) (+5)+(-7)+(-10)=-12 (f) (-6)-(-8)+(+4)=6

(g) (-3)+(-4)-(-7)=0 (h) (+4)-(-9)+5)=18


2.有向數(二)

(a) (+2)(+7)=14 (b) (-3)(-9)=27

(c) (-10)(+7)=-70 (d) (+5)(-3)=-15

(e) (+2)(+13)(+4)=104 (f) (-3)(-7)(-9)=-189

(g) (-3)(+12)(-5)=180 (h) (+4)(+17)(-3)=-204


3.有向數(三)

(a) (+144)÷(+12)=12 (b) (-81)÷(-9)=9

(c) (-169)÷(+13)=-13 (d) (+196)÷(-14)=-14

(e) (-8)×(+1.75)/(-5)= 2.8

(f) (-2.8)×(-4)=6.8 (but (-2.8)×(-4)/(-7) = -1.6)

(g) +3又1/4-(+2又1/2-1/-2)÷-1/4=15又1/4

(h) (÷5/7) (-22/1)-(5/6) (-9/20)=> Typo => (Assume) (5/7) (-22/15)-(5/6) (-9/20) = 1又71/168


有向數 (應用題) [算式+答案]

1.早上氣溫為-3度,午間氣溫上升了10度,晚間下降了12度,
求晚間的氣溫。 = -3 +10 -12 = -5

2.計算 (-3/4)×(-1/4)×(-7/8)÷(-7/16) = 3/8
(but (-3/4)×(-3/4)×(-7/8)÷(-7/16) = 1又1/8 )


3.某人站於水平面上10m,而海則深26m,問該人與海底的垂
直距離為多少?= 10m - (-26m) = 36m

4.若 a=+3、b=-3,且 c=-5,則 (ab+bc-2ac)/(+5-(6)+a)-ab/c的值是多少?

= ((+3)(-3)+(-3)(-5)-2(+3)(-5))/(+5-(6)+(+3))-(+3)(-3)/(-5)
= 27/35
2009-07-31 4:21 am
i am F.1
GIVE YOU SOME TIPS:

1.++=+ 2.--=+ 3 . +-=- 4. -+=-

1.有向數

(a) (-8)+(-5)=-13 (b) (+9)+(-2)=7

(c) (+7)-(+12)=-5 (d) (-5)-(-6)=1

(e) (+5)+(-7)+(-10)=-12 (f) (-6)-(-8)+(+4)=6

(g) (-3)+(-4)-(-7)=0 (h) (+4)-(-9)+5)=18


2.有向數(二)

(a) (+2)(+7)=14 (b) (-3)(-9)=27

(c) (-10)(+7)=-70 (d) (+5)(-3)=-15

(e) (+2)(+13)(+4)=104 (f) (-3)(-7)(-9)=-189

(g) (-3)(+12)(-5)=180 (h) (+4)(+17)(-3)=-204


3.有向數(三)

(a) (+144)÷(+12)=12 (b) (-81)÷(-9)=9

(c) (-169)÷(+13)=-13 (d) (+196)÷(-14)=-14

(e) (-8)×(+1.75)/(-5)= 2.8

(f) (-2.8)×(-4)=6.8 (but (-2.8)×(-4)/(-7) = -1.6)

(g) +3又1/4-(+2又1/2-1/-2)÷-1/4=15又1/4

(h) (÷5/7) (-22/1)-(5/6) (-9/20)=> Typo => (Assume) (5/7) (-22/15)-(5/6) (-9/20) = 1又71/168


有向數 (應用題) [算式+答案]

1.早上氣溫為-3度,午間氣溫上升了10度,晚間下降了12度,
求晚間的氣溫。 = -3 +10 -12 = -5

2.計算 (-3/4)×(-1/4)×(-7/8)÷(-7/16) = 3/8
(but (-3/4)×(-3/4)×(-7/8)÷(-7/16) = 1又1/8 )


3.某人站於水平面上10m,而海則深26m,問該人與海底的垂
直距離為多少?= 10m - (-26m) = 36m

4.若 a=+3、b=-3,且 c=-5,則 (ab+bc-2ac)/(+5-(6)+a)-ab/c的值是多少?

= ((+3)(-3)+(-3)(-5)-2(+3)(-5))/(+5-(6)+(+3))-(+3)(-3)/(-5)
= 27/35
參考: me


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