1.有向數
(a) (-8)+(-5)=____ (b) (+9)+(-2)=____
(c) (+7)-(+12)=____ (d) (-5)-(-6)=____
(e) (+5)+(-7)+(-10)=____ (f) (-6)-(-8)+(+4)=____
(g) (-3)+(-4)-(-7)=____ (h) (+4)-(-9)+5)=____
2.有向數(二)
(a) (+2)(+7)=____ (b) (-3)(-9)=____
(c) (-10)(+7)=____ (d) (+5)(-3)=____
(e) (+2)(+13)(+4)=____ (f) (-3)(-7)(-9)=____
(g) (-3)(+12)(-5)=____ (h) (+4)(+17)(-3)=____
3.有向數(三)
(a) (+144)÷(+12)=____ (b) (-81)÷(-9)=____
(c) (-169)÷(+13)=____ (d) (+196)÷(-14)=____
(-8)×(+1.75) (-2.8)×(-4)
(e) ---------------- =____ (f) ---------------=____
(-5) (-7)
1 1 1 -1
(g) 3-- － ( +2-- － --- ) ÷ --- = _____
4 2 -2 4
5 -22 5 -9
(h) ( + -- ) ( ------ ) － ( -- ) ( --- ) = _____
7 15 6 20
有向數 (應用題) [算式+答案]
1.早上氣溫為-3度，午間氣溫上升了10度，晚間下降了12度，
求晚間的氣溫。
3 3 7 7
2.計算 ( － -- ) × ( － -- ) × ( － -- ) ÷ ( － --- ) 。
4 4 8 16
3.某人站於水平面上10m，而海則深26m，問該人與海底的垂
直距離為多少？
ab+bc-2ac ab
4.若 a=+3、b=-3，且 c=-5，則 --------------- － --- 的值是多少？
+5-(-6)+a c
數學問題a_a
2009-07-27 4:04 am
回答 (2)
2009-07-27 4:58 am
✔ 最佳答案
1.有向數(a) (-8)+(-5)=-13 (b) (+9)+(-2)=7
(c) (+7)-(+12)=-5 (d) (-5)-(-6)=1
(e) (+5)+(-7)+(-10)=-12 (f) (-6)-(-8)+(+4)=6
(g) (-3)+(-4)-(-7)=0 (h) (+4)-(-9)+5)=18
2.有向數(二)
(a) (+2)(+7)=14 (b) (-3)(-9)=27
(c) (-10)(+7)=-70 (d) (+5)(-3)=-15
(e) (+2)(+13)(+4)=104 (f) (-3)(-7)(-9)=-189
(g) (-3)(+12)(-5)=180 (h) (+4)(+17)(-3)=-204
3.有向數(三)
(a) (+144)÷(+12)=12 (b) (-81)÷(-9)=9
(c) (-169)÷(+13)=-13 (d) (+196)÷(-14)=-14
(e) (-8)×(+1.75)/(-5)= 2.8
(f) (-2.8)×(-4)=6.8 (but (-2.8)×(-4)/(-7) = -1.6)
(g) +3又1/4－(+2又1/2－1/-2)÷-1/4=15又1/4
(h) (÷5/7) (-22/1)－(5/6) (-9/20)=> Typo => (Assume) (5/7) (-22/15)－(5/6) (-9/20) = 1又71/168
有向數 (應用題) [算式+答案]
1.早上氣溫為-3度，午間氣溫上升了10度，晚間下降了12度，
求晚間的氣溫。 = -3 +10 -12 = -5
2.計算 (-3/4)×(-1/4)×(-7/8)÷(-7/16) = 3/8
(but (-3/4)×(-3/4)×(-7/8)÷(-7/16) = 1又1/8 )
3.某人站於水平面上10m，而海則深26m，問該人與海底的垂
直距離為多少？= 10m - (-26m) = 36m
4.若 a=+3、b=-3，且 c=-5，則 (ab+bc-2ac)/(+5-(6)+a)－ab/c的值是多少？
= ((+3)(-3)+(-3)(-5)-2(+3)(-5))/(+5-(6)+(+3))－(+3)(-3)/(-5)
= 27/35
2009-07-31 4:21 am
i am F.1
GIVE YOU SOME TIPS:
1.++=+ 2.－－=+ 3 . +－=－ 4. －+=－
1.有向數
(a) (-8)+(-5)=-13 (b) (+9)+(-2)=7
(c) (+7)-(+12)=-5 (d) (-5)-(-6)=1
(e) (+5)+(-7)+(-10)=-12 (f) (-6)-(-8)+(+4)=6
(g) (-3)+(-4)-(-7)=0 (h) (+4)-(-9)+5)=18
2.有向數(二)
(a) (+2)(+7)=14 (b) (-3)(-9)=27
(c) (-10)(+7)=-70 (d) (+5)(-3)=-15
(e) (+2)(+13)(+4)=104 (f) (-3)(-7)(-9)=-189
(g) (-3)(+12)(-5)=180 (h) (+4)(+17)(-3)=-204
3.有向數(三)
(a) (+144)÷(+12)=12 (b) (-81)÷(-9)=9
(c) (-169)÷(+13)=-13 (d) (+196)÷(-14)=-14
(e) (-8)×(+1.75)/(-5)= 2.8
(f) (-2.8)×(-4)=6.8 (but (-2.8)×(-4)/(-7) = -1.6)
(g) +3又1/4－(+2又1/2－1/-2)÷-1/4=15又1/4
(h) (÷5/7) (-22/1)－(5/6) (-9/20)=> Typo => (Assume) (5/7) (-22/15)－(5/6) (-9/20) = 1又71/168
有向數 (應用題) [算式+答案]
1.早上氣溫為-3度，午間氣溫上升了10度，晚間下降了12度，
求晚間的氣溫。 = -3 +10 -12 = -5
2.計算 (-3/4)×(-1/4)×(-7/8)÷(-7/16) = 3/8
(but (-3/4)×(-3/4)×(-7/8)÷(-7/16) = 1又1/8 )
3.某人站於水平面上10m，而海則深26m，問該人與海底的垂
直距離為多少？= 10m - (-26m) = 36m
4.若 a=+3、b=-3，且 c=-5，則 (ab+bc-2ac)/(+5-(6)+a)－ab/c的值是多少？
= ((+3)(-3)+(-3)(-5)-2(+3)(-5))/(+5-(6)+(+3))－(+3)(-3)/(-5)
= 27/35
GIVE YOU SOME TIPS:
1.++=+ 2.－－=+ 3 . +－=－ 4. －+=－
1.有向數
(a) (-8)+(-5)=-13 (b) (+9)+(-2)=7
(c) (+7)-(+12)=-5 (d) (-5)-(-6)=1
(e) (+5)+(-7)+(-10)=-12 (f) (-6)-(-8)+(+4)=6
(g) (-3)+(-4)-(-7)=0 (h) (+4)-(-9)+5)=18
2.有向數(二)
(a) (+2)(+7)=14 (b) (-3)(-9)=27
(c) (-10)(+7)=-70 (d) (+5)(-3)=-15
(e) (+2)(+13)(+4)=104 (f) (-3)(-7)(-9)=-189
(g) (-3)(+12)(-5)=180 (h) (+4)(+17)(-3)=-204
3.有向數(三)
(a) (+144)÷(+12)=12 (b) (-81)÷(-9)=9
(c) (-169)÷(+13)=-13 (d) (+196)÷(-14)=-14
(e) (-8)×(+1.75)/(-5)= 2.8
(f) (-2.8)×(-4)=6.8 (but (-2.8)×(-4)/(-7) = -1.6)
(g) +3又1/4－(+2又1/2－1/-2)÷-1/4=15又1/4
(h) (÷5/7) (-22/1)－(5/6) (-9/20)=> Typo => (Assume) (5/7) (-22/15)－(5/6) (-9/20) = 1又71/168
有向數 (應用題) [算式+答案]
1.早上氣溫為-3度，午間氣溫上升了10度，晚間下降了12度，
求晚間的氣溫。 = -3 +10 -12 = -5
2.計算 (-3/4)×(-1/4)×(-7/8)÷(-7/16) = 3/8
(but (-3/4)×(-3/4)×(-7/8)÷(-7/16) = 1又1/8 )
3.某人站於水平面上10m，而海則深26m，問該人與海底的垂
直距離為多少？= 10m - (-26m) = 36m
4.若 a=+3、b=-3，且 c=-5，則 (ab+bc-2ac)/(+5-(6)+a)－ab/c的值是多少？
= ((+3)(-3)+(-3)(-5)-2(+3)(-5))/(+5-(6)+(+3))－(+3)(-3)/(-5)
= 27/35
參考: me
收錄日期: 2021-04-15 21:37:10
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090726000051KK01576