✔ 最佳答案
Since n satisfies both equations.
n^2 - an + b = 0 ...(1) and
n^2 - bn + a = 0....(2)
(1) - (2) we get
-an + b + bn - a = 0
n(b -a) = a - b
so n = -1.
(b)
Sub n = -1 into (1)
1 + a + b = 0
so a + b = -1.
(c)
sum of roots = m + n = a
m = a - n = a + 1.............(3)
sum of roots = n + y = b
y = b - n = b + 1...............(4)
so m + y = a + 1 + b + 1 = a + b + 2
my = (a + 1)(b + 1)
so the required equation is
x^2 - (a + b + 2) + (a + 1)(b + 1) = 0
2009-07-25 19:55:44 補充:
Last line should be x^2 - (a + b + 2)x + (a + 1)(b +1) = 0