定溫下，平衡式CH4+Cl2=CH3Cl+HCl
已知K=56,平衡時測得﹝CH4﹞e=0.2 , ﹝Cl2﹞e=0.4
﹝CH3cCl﹞e=﹝HCl﹞e , 求﹝CH3Cl﹞e=?
化學 平衡式 1題
2009-07-23 8:26 pm
回答 (2)
2009-07-23 8:51 pm
✔ 最佳答案
CH4 + Cl2 ≒ CH3Cl + HCl平衡時：
[CH4]e = 0.2
[Cl2]e = 0.4
設 [CH3Cl]e = [HCl]e = y
K = [CH3Cl]e•[HCl]e/[CH4]e•[Cl2]e
y²/(0.2)(0.4) = 56
y² = 4.48
y = 2.12
[CH3Cl]e = 2.12
2009-07-26 9:18 pm
平衡式為:CH4 + Cl2---> CH3Cl + HCl
平衡常數(K) = ( [CH3Cl]*[HCl] ) / ( [CH4]*[Cl2] )
又 [CH4]e= 0.2 , [Cl2]e=0.4 , [CH3Cl]e=[HCl]e
因此令[CH3Cl]e=[HCl]e= x
所以由平衡常數(K) = ( [CH3Cl]*[HCl] ) / ( [CH4]*[Cl2] )可算出 x值
56 = ( x*x) / ( 0.2 *0.4 )
因此 x = 2.1166 ；所以[CH3Cl]e=[HCl]e= 2.12
平衡常數(K) = ( [CH3Cl]*[HCl] ) / ( [CH4]*[Cl2] )
又 [CH4]e= 0.2 , [Cl2]e=0.4 , [CH3Cl]e=[HCl]e
因此令[CH3Cl]e=[HCl]e= x
所以由平衡常數(K) = ( [CH3Cl]*[HCl] ) / ( [CH4]*[Cl2] )可算出 x值
56 = ( x*x) / ( 0.2 *0.4 )
因此 x = 2.1166 ；所以[CH3Cl]e=[HCl]e= 2.12
參考: me
收錄日期: 2021-04-13 16:44:30
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