How do you solve for x? What does it equal?

2009-07-20 5:20 pm
2 log_5x -log_5 2=log_5 18

回答 (3)

2009-07-20 7:54 pm
✔ 最佳答案
Let log be log to base 5

2 log x - log 2 = log 18

log [ x^2 / 2 ] = log 18

x^2 / 2 = 18

x^2 = 36

x = 6 is acceptable solution.
2009-07-20 6:02 pm
2log_5(x) - log_5(2) = log_5(18)
log_5(x^2) - log_5(2) = log_5(18)
log_5(2x^2) = log_5(18)
2x^2 = 18
x^2 = 18/2
x = ±√9
x = ±3
(BTW, x cannot be negative, so x only equals 3.)
2009-07-20 5:52 pm
2 log_5 (x) - log_5 (2) = log_5 (18)

log_5 (x²) - log_5 (2) = log_5 (18)

log_5 (x²/2) = log_5 (18)

x²/2 = 18

x² = 36

x = 6


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