Let k = ʃ(from π to 0) (x cos2x) dx.
Evaluate ʃ(from sqrt(2π) to 0) [2x(xcosx2)2]dx in terms of k.
difficult integration
2009-07-19 2:17 am
回答 (1)
2009-07-19 3:34 am
收錄日期: 2021-04-22 00:46:13
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