Simplify: (-4x^3y^2)(-5^2y^4)?

2009-07-15 1:51 pm

回答 (9)

2009-07-16 10:48 am
✔ 最佳答案
(-4x^3y^2)(-5^2y^4)
=(-4x^3y^2)(-25y^4)
=100x^3y^6 answer//
2016-11-10 10:34 am
pull out each and everything it truly is difficulty-unfastened to the the two certainly one of them. fifty two is divisible by using four y's are difficulty-unfastened to the two. very final answer will seem something like -n(x's y's)(n y's) you are able to in all probability be certain the rest your self.
2009-07-15 8:48 pm
20x^5y^6
2009-07-15 2:35 pm
(-4x^3y^2)(-5x^2y^4)
= (-4 * -5)[x^(3 + 2)]y^(2 + 4)]
= 20[x^5][y^6]
= 20x^5y^6
2009-07-15 2:22 pm
-100x^3y^6
2009-07-15 2:17 pm
Rule. a^n^m = a^mn
Rule. a^n * a^m = a^(n+m)
You can't combine powers of different bases unless you have a common denominator of some kind.

Not sure if your question is (-4.x^6y).(-(5^8y))
or (-4.x^6y).((-5)^8y)
Going for the second case

You can't multiply the -4 by the -5 because its not -5, it's (-5)^8y
E.g. 2^3 * 5^2 = 10^6 is obviously rubbish
You can't combine the powers because there's no common base or common denominator in the base.
Without rearranging you can get.
-4(x^6y)( (-5)^8y)

Perhaps you could rewrite as
-4x^6y . -5 ^ 8y
= -4 * x^3^2y * (-5)^4^2y
to give -4 * (x^3 *(-5)^4)^2y
= -4 * (625x^3)^2y

That's a bit neater - best I can do.
2009-07-15 2:02 pm
I'm not really sure but my answer's 4x^ -y^ -10^ +8
2009-07-15 1:56 pm
20x^5y^6
2009-07-15 1:57 pm
i would totally noe how to do this
except people would give you different answers using different ways
so it would me easier if you added additional details like algebra etc.
the name of the chapter or unit that question your doing..
but obviously its an expression..is it expanding or...
add more details
i'd sure answer

told you so, everyones giving diffrent answers. but hey i got the right answer:

(-4*x^3*y^2)*(-5^2*y^4) evaluates to
100y^6x3
100y^18
參考: easy steps to get the answer its one click away: http://www.webmath.com/_answer.php


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