Find the value of x log x 289/25 = 2?

I assume you mean log (base-x) 289/25 = 2

Note that x² = 289/25
x = 17/5 = 3.4

log_x(289/25) = 2
289/25 = x^2
x = ±√(289/25)
x = ±√[(17^2)/(5^2)]
x = ±17/5 (±3.4)

BTW, x cannot be negative. Therefore, x only equals positive 17/5 (3.4).

quick question, is it xlog(x(289/25)) or is the x in front just finishing the instructions w/o any punctuation? either way i will show you both ways.

1. xlog(289x/25) = 2
Divide both sides by x (since the log of 0 is undefined we can safely do this without worrying whether or not the x is equal to zero.

log(289x/25) = 2/x

Next, set each both sides of the equation as the exponent of 10.

10^log(289x/25) = 10^(2/x)

the 10^log cancels out and you are left with:

(289x/25) = 10^(2/x); however, in such a scenario, you are left to find the answer on a calculator as we are unable to isolate the 'x' variable without the help of a computer of some sort.

now, if it is as i -think- it should be read:

log (289x/25) = 2

set both sides of the equation as exponents of 10 to cancel out the log

(289x/25) = 10^2

10^2 = 100, then multiple the 25 out of the denominator to get

289x = 2500, divide by 289 to leave the x alone on the left side.

x = 2500/289 = 8.65051903114

do you mean find the value of x given that log (x*289/25)=2? and by log do you mean to base 10? if so
log(x*289/25)=2
x*289/25=10^2=100
x=100/(289/25)
x=25*100/289
x=2500/289~8.65

What does log x 289/25 mean?