x+5y=10 find the slope?

x + 5y = 10

5y = 10 - x

y = 2 - (1/5)x

slope = -(1/5)

x + 5y=10

When the line is in general form Ax+By=C the gradient is -A/B.
So for your equation A=1 and B=5 so the gradient is -1/5

5y X 10

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you really don't need points. Just solve for y by subtracting x from both sides and dividing by 5. So your new equation looks like this: y=(-x+10)/5. Whenever you have one term in the denominator you can separate you fractions. so is (a+b)/c then it is equivalent to a/c + b/c. IN your equation then you have -x/5 and 10/5. YOu can certainly get a whole number when you divide 10/5 which is two. For -x/5 remember that whenever there is no number next to a variable that number is either 1 or -1 depending on the sign. You have a - sign next to x. So that looks like -1/5 x. So your whole equation is y=-1/5 x + 2. Put a point on your graph at y=2 because that is your y-intercept. Now start from two and go down 1 and over to the right 5. You can also go up one and over to the left 5. Just remember that the direction up and right or positive and down and left are negative.

5 y = - x + 10

y = (- 1 / 5 ) x + 2

m = - 1 / 5

in ax+by=c,m=-a/b
here,m=-1/5=0.2

the slope of Ax+By=c is -A/B which is - coefficient of x/(coefficient of y)in your case A=1,B=5 then the slope is -1/5=-0.2

y = mx + b (the general form of a linear equation)
(m = slope and b = y-intercept)

Solve for y.
x + 5y = 10
5y = -x + 10
y = (-x + 10)/5
y = -x/5 + 10/5
y = -1/5(x) + 2

Slope: -1/5 (-0.2)

If y=mx+c m is slope
X+5y=10
So y=-(1/5)x+2
So slope is -1/5

put the equation into y=mx+c format
y=(10-x)/5
y=-X/5+2
y=(-1/5)x+2
hence slope equals -1/5