Mr.Choi有一個蛋糕, 他跟Miss.Tang分享。Mr.Choi取了蛋糕的3份,剩下的給了Miss.Tang。如果Mr.Choi把他的蛋糕的100克給予Miss.Tang , 那麼Mr.Choi所得的份量就是Miss.Tang的兩倍。
請問蛋糕的原重量是多少??
要以方程式回答 ::
Let X be the weight of the cake
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各位回答的朋友只要列第1條式就可以了, 謝謝
數學算術題 小六
2009-07-14 7:33 am
回答 (5)
2009-07-15 7:36 am
✔ 最佳答案
Mr.Choi有一個蛋糕, 他跟Miss.Tang分享。Mr.Choi取了蛋糕的3份,剩下的給了Miss.Tang。如果Mr.Choi把他的蛋糕的100克給予Miss.Tang , 那麼Mr.Choi所得的份量就是Miss.Tang的兩倍。請問蛋糕的原重量是多少??
Let y = 一份重量
3 y = 100 gram
3y + 2(3y) = x
所以 :
x = (100/3)*3 + (100/3) *6
2009-07-15 6:12 am
Mr.Choi本來已蛋糕分了幾份(不知數) , 而他取了其中3份
2009-07-14 9:39 am
X(總重)，Y(全部有幾份)
X*3/Y-100 = 2( (Y-3)/Y+100)
if Y is N 1,2,3,....
X = 300/7, 120,300,1200 (負不合，小於300不合)
X*3/Y-100 = 2( (Y-3)/Y+100)
if Y is N 1,2,3,....
X = 300/7, 120,300,1200 (負不合，小於300不合)
參考: 自己
2009-07-14 7:42 am
"Mr.Choi取了蛋糕的3份" 是甚麼意思?
2009-07-15 11:41:26 補充：
Let x be the weight of the cake
Let n be the number of pieces
Weight of each piece = x/n
Originally Mr Choi has 3(x/n) by weight
And Miss Tang has (n-3)(x/n) by weight
After Mr Choi gave 100g to Miss Tang,
3x/n – 100 = 2[(n – 3)x/n + 100] … (1)
n > 3 … (2)
x > 0 … (3)
2009-07-15 11:41:26 補充：
Let x be the weight of the cake
Let n be the number of pieces
Weight of each piece = x/n
Originally Mr Choi has 3(x/n) by weight
And Miss Tang has (n-3)(x/n) by weight
After Mr Choi gave 100g to Miss Tang,
3x/n – 100 = 2[(n – 3)x/n + 100] … (1)
n > 3 … (2)
x > 0 … (3)
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