if (27^2x)/3=(1/9)^4y, then y= -((6x-1)/8)
i can't calculate the ans. correctly, could anyone help me?
change of subject 's problem
2009-07-13 11:03 pm
回答 (1)
2009-07-13 11:17 pm
✔ 最佳答案
(272x)/3 = (1/9)4y[(33)2x]/31 = (1/32)4y
(36x)(3-1) = 1/(32)4y
36x-1=1/38y
36x-1=3-8y
6x-1=-8y
y=-(6x-1)/8
收錄日期: 2021-04-23 23:18:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090713000051KK01127