25x^2 + 10x + 1 = 0 SOLVE?
回答 (5)
2009-07-13 6:30 am
✔ 最佳答案
25x² + 10x + 1 = 0(5x+1)² = 0
5x+1 = 0
x = {-1/5, -1/5} double root
2009-07-13 6:08 pm
25x^2 + 10x + 1 = 0
25x^2 + 5x + 5x + 1 = 0
(25x^2 + 5x) + (5x + 1) = 0
5x(5x + 1) + 1(5x + 1) = 0
(5x + 1)(5x + 1) = 0
5x + 1 = 0
5x = -1
x = -1/5 (-0.2)
â´ x = -1/5 (-0.2)
25x^2 + 5x + 5x + 1 = 0
(25x^2 + 5x) + (5x + 1) = 0
5x(5x + 1) + 1(5x + 1) = 0
(5x + 1)(5x + 1) = 0
5x + 1 = 0
5x = -1
x = -1/5 (-0.2)
â´ x = -1/5 (-0.2)
2009-07-13 2:52 pm
( 5 x + 1 ) ( 5 x + 1 ) = 0
x = - 1/5
x = - 1/5
2009-07-13 1:50 pm
x= -1/5
2009-07-13 1:31 pm
Solving:
25x^2 + 10x + 1 = 0 is a perfec squared., therefore
(5x + 1)^2 = 0
* 5x + 1 = 0 ==> x = -1/5
Since (5x + 1)^2 that means
the equation has double (same values) solution is x = -1/5
Good Luck!
25x^2 + 10x + 1 = 0 is a perfec squared., therefore
(5x + 1)^2 = 0
* 5x + 1 = 0 ==> x = -1/5
Since (5x + 1)^2 that means
the equation has double (same values) solution is x = -1/5
Good Luck!
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