25x^2 + 10x + 1 = 0 SOLVE?

25x² + 10x + 1 = 0
(5x+1)² = 0
5x+1 = 0
x = {-1/5, -1/5} double root

25x^2 + 10x + 1 = 0
25x^2 + 5x + 5x + 1 = 0
(25x^2 + 5x) + (5x + 1) = 0
5x(5x + 1) + 1(5x + 1) = 0
(5x + 1)(5x + 1) = 0

5x + 1 = 0
5x = -1
x = -1/5 (-0.2)

∴ x = -1/5 (-0.2)

( 5 x + 1 ) ( 5 x + 1 ) = 0

x = - 1/5

x= -1/5

Solving:

25x^2 + 10x + 1 = 0 is a perfec squared., therefore
(5x + 1)^2 = 0

* 5x + 1 = 0 ==> x = -1/5
Since (5x + 1)^2 that means
the equation has double (same values) solution is x = -1/5
Good Luck!