請問這條數點計？
(a＋b)^2＝
數學問題？請幫忙
2009-07-11 11:34 am
回答 (4)
2009-07-11 3:08 pm
✔ 最佳答案
(a＋b)^2= (a + b) x (a + b)
= a^2 + ab + ab + b^2
= a^2 + 2ab + b^2
2009-07-11 11:50:23 補充：
(a＋b)^2
= (a + b) x (a + b)
= a x (a + b) + b x (a + b)
= a^2 + ab + ab + b^2
= a^2 + 2ab + b^2
2009-07-13 6:00 pm
(a+b)^2
=(a+b)(a+b)
=a(a+b)+b(a+b)
=a^2+ab+ab+b^2
=a^2+2ab+b^2(這是公式,必記)
=(a+b)(a+b)
=a(a+b)+b(a+b)
=a^2+ab+ab+b^2
=a^2+2ab+b^2(這是公式,必記)
參考: me
2009-07-11 7:15 pm
用恆等式:
(a+b)^2 = a^2+2ab+b^2
(a+b)^2 = a^2+2ab+b^2
收錄日期: 2021-04-23 20:38:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090711000051KK00243