find the square
-(4y - 5)^2
Algebra 2 help needed: find the square -(4y - 5)^2?
2009-07-09 4:21 pm
回答 (6)
2009-07-09 4:26 pm
✔ 最佳答案
- (4y - 5)^2Square the binomial
- (16y^2 - 40y + 25)
Distribute the negative
- 16y^2 + 40y - 25
QED
2009-07-09 5:34 pm
-(4y - 5)^2
= -(4y - 5)(4y - 5)
= -[4y(4y) - 4y(5) - 5(4y) + 5(5)]
= -[16y^2 - 20y - 20y + 25]
= -[16y^2 - 40y + 25]
= -16y^2 + 40y - 25
= -(4y - 5)(4y - 5)
= -[4y(4y) - 4y(5) - 5(4y) + 5(5)]
= -[16y^2 - 20y - 20y + 25]
= -[16y^2 - 40y + 25]
= -16y^2 + 40y - 25
2009-07-09 4:34 pm
-(4y - 5)^2
=-(4y-5)(4y-5)
=-(16y^2-40y+25)
=-16y^2+40y-25 answer//
=-(4y-5)(4y-5)
=-(16y^2-40y+25)
=-16y^2+40y-25 answer//
2009-07-09 4:28 pm
-16y^2+40y-25
2009-07-09 4:26 pm
FOIL Method:
-(16y^2 -20y -20y +25)
= -16y^2 + 40y - 25
-(16y^2 -20y -20y +25)
= -16y^2 + 40y - 25
2009-07-09 4:25 pm
-( 16y^2 -40y + 25)
= -16y^2 + 40y - 25
= -16y^2 + 40y - 25
收錄日期: 2021-05-01 12:37:31
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