-3(x-9)=1/2(4x+12) please solve for me?

(4x + 12) * 1/2 = 2x + 6

-3x + 27 = 2x + 6
5x = 21
x = 21/5

-3(x - 9) = 1/2(4x + 12)
-3(x) + 3(9) = (4x + 12)/2
-3x + 27 = 2x + 6
-3x - 2x = -27 + 6
-5x = -21
x = 21/5 (4.2)

multiply both sides of the equation by 2 (to eliminate the 1/2)
--> -6(x-9) = 1(4x+12)
now remove the brackets by multiplying everything inside the brackets by everything outside them
--> -6x + 54 = 4x +12
rearrange the equation in order to have your unknowns on one side and your constants on the other
--> -6x - 4x = 12 - 54
--> -10x = -42
--> x = -42/-10
x = 21/5

ok first you have to distribute. -3(x-9) is going to be -3x+27. you multiply -3*x and -3*-9. then 1/2(4x+12) is going to be 2x+6. you multiply 1/2*4 and 1/2*12. so now you have -3x+27=2x+6. add 3x to both sides. so now you have 27=5x+6. subtract 6 from both sides. so now you have 27=5x. divide 27 by 5 and you get 4.2. so x=4.2 and to check your answer substitute 4.2 for x. then -3*4.2+27=14.4 and 2*4.2+6=14.4.

-3x + 27 = 2x + 6
21 = 5x
x = 21/5

- 6 ( x - 9 ) = 4 x + 12

- 6x + 54 = 4 x + 12

42 = 10 x

x = 42 / 10

x = 21 / 5

-3(x-9)=1/2(4x+12)
-3x+27=2x+6 distribute
27=5x+6
21=5x
x=21/5