Solve equation x^3 + x^2 = 0?
回答 (6)
2009-07-07 5:01 am
✔ 最佳答案
x³ + x² = 0So first you factor out an x²:
x²(x + 1) = 0
So now you set both equal to zero:
x² = 0............x + 1 = 0
x = 0..............x = -1
So:
x = 0 and -1 <==answer
2009-07-07 8:39 am
x^3 + x^2 = 0
x^2(x + 1) = 0
x^2 = 0
x = 0
x + 1 = 0
x = -1
∴ x = -1, 0
x^2(x + 1) = 0
x^2 = 0
x = 0
x + 1 = 0
x = -1
∴ x = -1, 0
2009-07-07 5:06 am
x^3=-x^2
x=0
and
x=-1
x=0
and
x=-1
2009-07-07 5:02 am
First, factor out an x^2.
so you have: x^2(x+1) = 0
Since the left side is multiplied together and the right is a zero, we know that one of the terms from the left side is zero. So we can write 2 equations.
x^2 = 0 or x + 1 = 0.
sqrt(x^2) = 0
x = 0 or x = -1
Those are your two final answers.
so you have: x^2(x+1) = 0
Since the left side is multiplied together and the right is a zero, we know that one of the terms from the left side is zero. So we can write 2 equations.
x^2 = 0 or x + 1 = 0.
sqrt(x^2) = 0
x = 0 or x = -1
Those are your two final answers.
2009-07-07 5:01 am
0 and -1
0^3 + 0^2 = 0 + 0 = 0
-1^3 + -1^2 = -1 + 1 = 0
0^3 + 0^2 = 0 + 0 = 0
-1^3 + -1^2 = -1 + 1 = 0
2009-07-07 5:01 am
x^3 + x^2 = 0?
Factor and use the distributive law
x*x*x + x*x = 0
x*x*(x + 1) = 0
There are only 2 ways that this product can be 0
x = 0, since 0*0*(1) = 0
x = -1 since (-1)*(-1)*0 = 0
Your 3 solutions are 0,0,-1 since every cubic equation has 3 solutions.
Factor and use the distributive law
x*x*x + x*x = 0
x*x*(x + 1) = 0
There are only 2 ways that this product can be 0
x = 0, since 0*0*(1) = 0
x = -1 since (-1)*(-1)*0 = 0
Your 3 solutions are 0,0,-1 since every cubic equation has 3 solutions.
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