finding y-intercepts in algebra?

The standard slope-intercept form of a straight line is

y = mx + b

where

m = slope
b = y-intercept

Compare the given equation

y = -(3/2)x - 2

with the standard slope-intercept form, then your y-intercept is equal to -2.

Generally, given any equation though, the y-intercept is determined by setting x = 0. By doing this (setting x = 0), the equation can then be simply solved for "y."

Hope this helps.

y = mx + b (m = slope and b = y-intercept)

y = -3/2(x) - 2
Y-intercept: -2

The y intercept is the value(s) for y when x = 0.

y = (-3/2)(0)-2
y = -2

The formula for this problem is
y=mx + b

1. Plug in your coefficients, or the numbers you have been given for the formula.
y= -3/2x-2

2. M is your slope. M in this problem is -3/2. B is your y-intercept. B in this problem is -2.

Your y-intercept is -2, not +2 because the formula is y=mx + b, not minus. so it is read, "y equals negative three halves x PLUS NEGATIVE two.

Presentation is unclear.

Assuming that you mean :-

y = (-3/2) x - 2

y intercept is y = - 2