2(x – 4) = 5x + 7 – 3x?

2009-07-06 5:45 pm
how do you solve this when 2x is subtracted by 2x??

回答 (8)

2009-07-06 5:57 pm
✔ 最佳答案
i'll do it step by step

multiply using distributive property and add like terms
2x-8 = 2x+7

subtract 2x from both sides
-8 = 7

-8 does not equal 7 and therefore the question has no solution
2016-11-08 1:31 pm
(5x^7 - 3x^4 +2x^2 -10x +2)/(x^2-x+a million) = (5x^7 - 3x^4 +2(x^2-x+a million) - 8x)/(x^2-x+a million) = (5x^7 - 3x^4 - 8x)/(x^2-x+a million) + 2 ........ ....... (5x^5)(x^2-x+a million) = 5x^7 - 5x^6 + 5x^5 = [(5x^5)(x^2-x+a million) + 5x^6 - 5x^5 - 3x^4 - 8x]/(x^2-x+a million) + 2 = (5x^6 - 5x^5 - 3x^4 - 8x)/(x^2-x+a million) + 2 + 5x^5 ........ ....... 5x^4(x^2-x+a million) = 5x^6 - 5x^5 + 5x^4 = (5x^4)(x^2-x+a million) - 8x^4 - 3x^4)/(x^2-x+a million) + 2 + 5x^5 = -11x^4/(x^2-x+a million) + 2 + 5x^5 + 5x^4 ........ ....... (-11x^2)(x^2-x+a million) = -11x^4 + 11x^3 - 11x^2 = ((-11x^2)(x^2-x+a million) -11x^3 - 11x^2)/(x^2-x+a million) + 2 + 5x^5 = (-11x^3 - 11x^2)/(x^2-x+a million) + 2 + 5x^5 - 11x^2 ........ ....... (-11x)(x^2-x+a million) = -11x^3 + 11x^2 + 11x = ((-11x)(x^2-x+a million) - 22x^2 + 11x)/(x^2-x+a million) + 2 + 5x^5 - 11x^2 = (-22x^2 + 11x)/(x^2-x+a million) + 2 + 5x^5 - 11x^2 - 11x ........ ....... -11(x^2-x+a million) = -22x^2 + 11x - 11 = (-11(x^2-x+a million) + 11)/(x^2-x+a million) + 2 + 5x^5 - 11x^2 - 11x = 11/(x^2-x+a million) + (x^2-x+a million) + 2 + 5x^5 - 11x^2 - 11x - 11 answer: 5x^5 - 11x^2 - 11x - 9 + [11/(x^2-x+a million)]
2009-07-06 5:55 pm
2(x - 4) = 5x + 7 - 3x
2(x) - 2(4) = 5x + 7 - 3x
2x - 8 = 5x - 3x + 7
2x - 8 = 2x + 7
2x - 2x = 8 + 7
0 = 15
(no solution)
2009-07-06 5:53 pm
2x - 8=5x + 7 -3x

2x-5x+3x=8+7

0x = 1

the answer is 'undefined'. any number including zero divided by any number equals 'undefined' or INFINITY,

try it
2009-07-06 5:53 pm
impossible
2009-07-06 5:51 pm
The conclusion that -8 = 7 is impossible so the equation is false
2009-07-06 5:51 pm
you don't - there is no solution.
2009-07-06 5:50 pm
2x-8=2x+7

-8=7

Hence the equation has no solution


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