Solve for x using the square root property: 2x2 = 40?

2x² = 40

first, divide both sides by 2:

x² = 20

Now, take the square root of both sides, remmebering that (-2)² and 2² both equal 4, so the result is that you ± the right side:

x = ±√20

Now simplify the radical:
x = ±√(4 * 5)
x = 2±√5

2x^2 = 40 Divide the two sides by way of 2, x^2 = 20 The sq. root assets potential that, as quickly as we take the sq. root of the two sides, we ought to incorporate the two helpful and detrimental strategies. it is represented as "plus or minus" after taking the sq. root. x = +/- sqrt(20) we are able to decrease sqrt(20) as 2sqrt(5). x = +/- 2sqrt(5)

2x^2 = 40
x^2 = 40/2
x = ±√20
x = ±√(2^2 * 5)
x = ±2√5

2x² = 40

First you wanna divide by 2 on both sides:
x² = 20

Now square root both sides:
x = ±√20

Break down the root:
x = ±2√5 <==Answer

2x² = 40
x² = 20
x = ±√20
x = ± 2√5

2x^2 = 40
x^2 = 20
x = +- sqrt(20)
x = +- 2sqrt(5)

:D

2x2=40
2*2*x=40
4x=40
x=10
10*2*2=40