(x-4)(x^2+4x+16) How do you FOIL this?

= (x - 4)(x² + 4x + 16)
= x³ + 4x² + 16x - 4x² - 16x - 64
= x³ - 64

Answer: x³ - 64

x*x^2=x^3
x*4x=4x^2
x*16=16x
-4*x^2=-4x^2
-4*4x=-16x
-4*16=-64

x^3+4x^2+16x-4x^2-16x-64

ans. x^3-64

=x^3+4x^2+16x-4x^2-16x-64
=x^3-64

Multiply x through, then -4, and add like terms.

x(x^2 + 4x + 16) + (-4)(x^2 + 4x + 16)

x^3 + 4x^2 + 16x - 4x^2 - 16x - 64

x^3 - 64 is the result.

so basically go in some sort of order
i did this:

x times x^2 = x^3
x times 4x = 4x^2
x times 16 = 16x

then do the same for -4

then just add the like terms together :)

Invoke the almighty distributive property.

(x-4)*(x^2+4x+16)

(x-4)*x^2 + (x-4)*4x + (x-4)*16

x^3 - 4x^2 + 4x^2 - 16x + 16x - 64

x^3 - 64

Good luck. =)

(x - 4)(x^2 + 4x + 16)
= x(x^2) - 4(x^2) + x(4x) - 4(4x) + x(16) - 4(16)
= x^3 - 4x^2 + 4x^2 - 16x + 16x - 64
= x^3 - 64

FOIL ability First, Outer, inner, final. What meaning for 5, 6, 7, 8, 9 is you do the multiply the 1st set in each and each parentheses. Then multiply the outer set and the two upload/subtract reckoning on the equation, then multiply the indoors and upload/subtract, then you definately multiply the final set of each and every parentheses. i will do the 1st one for you. 5. (x - 4)(x + 8) F = (multiply first set that's x * x) = x² O = (mutlipy the outter set that's +8 * x) = 8x I = (multiply the indoors set that's -4 * x) = -4x L = (multiply the final of each and every set that's +8 * -4) = -32 x² + 8x - 4x - 32 ( answer = x² + 4x - 32 attempt the others on your person ... basically would desire to take the time on them.

x^3 + 4x^2 + 16 x
____- 4x^2 - 16 x - 64

x^3 - 64