whats the solution to |-7x| ≤ 7?

-7x<=+7
x>=1
7x<=7
x<=1

|- 7x| <= 7
- 7x <= 7
- x <= 1
x >= - 1

|- 7x| <= - 7
- 7x <= - 7
- x <= - 1
x <= 1

Answer: x >= - 1, x <= 1

|-7x| ≤ 7
-7x ≤ 7 -- or -- -7x ≥ -7

-7x ≤ 7
x ≥ 7/(-7)
x ≥ -1

-7x ≥ -7
x ≤ -7/(-7)
x ≤ 1

∴ -1 ≤ x ≤ 1

- 7 ≤ - 7x ≤ 7

- 7x ≤ 7 ,___________- 7x ≥ - 7

- 7 ≤ 7x , __________7 ≥ 7x

x ≥ - 1___________x ≤ 1

{ x : - 1 ≤ x ≤ 1 , x Є R }

|-7x| ≤ 7
(7x)/7 ≤ 7/7
x ≤ 1

what's ever inside has to be 'equal' to the -/+ of the outside
don't fprget the - rule and inequalities

same as I7xI<=7
-7<=7x<=7
-1 <=x <=1