how do i evaluate (27)^-4/3?
回答 (4)
2009-07-05 7:06 am
✔ 最佳答案
3^-1/4=1/3^4=1/81
2009-07-05 2:01 pm
27^(-4/3)
= 1/27^(4/3) ................. note that (3)³ = 27
= 1/((3)³)^(4/3)
= 1/ (3)^4
= 1/81
Answer: 1/81
= 1/27^(4/3) ................. note that (3)³ = 27
= 1/((3)³)^(4/3)
= 1/ (3)^4
= 1/81
Answer: 1/81
2009-07-05 5:08 pm
27^(-4/3)
= ³â(27^-4)
= ³â[1/(27^4)]
= ³â{1/[(3^3)^4]}
= ³â{1/[(3^4)^3]}
= 1/(3^4)
= 1/81
= ³â(27^-4)
= ³â[1/(27^4)]
= ³â{1/[(3^3)^4]}
= ³â{1/[(3^4)^3]}
= 1/(3^4)
= 1/81
2009-07-05 2:10 pm
( 27) ^-4/3= cube root of 27 raise to the -4 power
cube root of 27=3 ^-4 = 3^ 1/4 = 1/81
cube root of 27=3 ^-4 = 3^ 1/4 = 1/81
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