how do i evaluate (27)^-4/3?
回答 (4)
27^(-4/3)
= 1/27^(4/3) ................. note that (3)³ = 27
= 1/((3)³)^(4/3)
= 1/ (3)^4
= 1/81
Answer: 1/81
27^(-4/3)
= ³â(27^-4)
= ³â[1/(27^4)]
= ³â{1/[(3^3)^4]}
= ³â{1/[(3^4)^3]}
= 1/(3^4)
= 1/81
( 27) ^-4/3= cube root of 27 raise to the -4 power
cube root of 27=3 ^-4 = 3^ 1/4 = 1/81
收錄日期: 2021-05-01 12:33:41
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