(x² + 5x + 6) ÷ (x + 2 )?
回答 (8)
2009-07-05 6:52 am
✔ 最佳答案
...........x+3 answer//.........---------------
...x+2|x^2+5x+6
.........-(x^2+2x)
........-----------------
...............3x+6
.............-(3x+6)
..............----------
...................0
another method is:
..x^2+5x+6
=----------------
.......x+2
..(x+2)(x+3)
=--------------- x+2 is cancel
.......x+2)
=x+3 answer//
2009-07-05 1:43 pm
= (x² + 5x + 6)/(x + 2)
= ([x + 2][x + 3])/(x + 2)
= x + 3
Answer: x + 3
Checking back to the dividend, x² + 5x + 6:
= (x + 3)(x + 2)
= x(x) + x(2) + 3(x) + 3(2)
= x² + 2x + 3x + 6
= x² + 5x + 6
= ([x + 2][x + 3])/(x + 2)
= x + 3
Answer: x + 3
Checking back to the dividend, x² + 5x + 6:
= (x + 3)(x + 2)
= x(x) + x(2) + 3(x) + 3(2)
= x² + 2x + 3x + 6
= x² + 5x + 6
2009-07-05 5:25 pm
(x^2 + 5x + 6)/(x + 2)
= (x^2 + 3x + 2x + 6)/(x + 2)
= [(x^2 + 3x) + (2x + 6)]/(x + 2)
= [x(x + 3) + 2(x + 3)]/(x + 2)
= [(x + 3)(x + 2)]/(x + 2)
= x + 3
= (x^2 + 3x + 2x + 6)/(x + 2)
= [(x^2 + 3x) + (2x + 6)]/(x + 2)
= [x(x + 3) + 2(x + 3)]/(x + 2)
= [(x + 3)(x + 2)]/(x + 2)
= x + 3
2009-07-05 3:40 pm
(x² + 5x +6)
-------------------- =
(x + 2)
(x+2) (x+3)
----------------- =
(x + 2)
cancel (x + 2)....
(x + 3)
-------------------- =
(x + 2)
(x+2) (x+3)
----------------- =
(x + 2)
cancel (x + 2)....
(x + 3)
2009-07-05 1:54 pm
(x+2)(x+3)/ x+2
x+3 x+2 's cancel out
x+3 x+2 's cancel out
2009-07-05 1:42 pm
x+3
2009-07-05 1:40 pm
(x^2 + 5x + 6) / (x + 2 )
= [(x + 2)(x + 3)] / (x + 2)
= x + 3
= [(x + 2)(x + 3)] / (x + 2)
= x + 3
2009-07-05 1:40 pm
x+3
收錄日期: 2021-05-01 12:34:34
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