1-1/sin2@
答案是-1/tam2@
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三角學化簡一問
2009-07-04 9:24 pm
回答 (1)
2009-07-04 9:26 pm
✔ 最佳答案
1 - 1/sin^2 x= (sin^2 x - 1)/sin^2 x
=-cos^2 x/sin^2 x
= - 1/tan^2 x.
收錄日期: 2021-04-25 22:43:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090704000051KK00738