factor in the lowest terms -2x-8/x^+2x-8?
回答 (4)
2009-07-03 6:59 am
✔ 最佳答案
=-2(x+4)/(x+4)(x-2)==2/(2-x)
2009-07-03 5:20 pm
= (- 2x - 8)/(x² + 2x - 8)
= (- 2[x + 4])/([x + 4][x - 2])
= - 2/(x - 2)
Answer: - 2/(x - 2) OR 2/(2 - x)
= (- 2[x + 4])/([x + 4][x - 2])
= - 2/(x - 2)
Answer: - 2/(x - 2) OR 2/(2 - x)
2009-07-03 1:54 pm
= -2/(x-2)
2009-07-03 2:07 pm
(-2x - 8)/(x^2 + 2x - 8)
= [-2(x + 4)]/(x^2 + 4x - 2x - 8)
= [-2(x + 4)]/[(x^2 + 4x) - (2x + 8)]
= [-2(x + 4)]/[x(x + 4) - 2(x + 4)]
= [-2(x + 4)]/[(x + 4)(x - 2)]
= -2/(x - 2)
= [-2(x + 4)]/(x^2 + 4x - 2x - 8)
= [-2(x + 4)]/[(x^2 + 4x) - (2x + 8)]
= [-2(x + 4)]/[x(x + 4) - 2(x + 4)]
= [-2(x + 4)]/[(x + 4)(x - 2)]
= -2/(x - 2)
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