can someone help with this?? Make x the subject 6(x + 3y) = 5?
回答 (5)
2009-07-03 6:25 am
✔ 最佳答案
6(x + 3y) = 56x + 15y = 5
6x = 5 - 15y
x = (5 - 15y)/6
Answer: x = (5 - 15y)/6 OR x = 5/6 - 5/2y
2009-07-03 3:50 pm
First, we have to expand:
6(x + 3y) = 5
6x + 18y = 5
Move 18y to the other side. Don't forget that when moving numbers/variables across the equal sign, we must change the numbers/variables to to opposite sign:
6x = 5 - 18y
Divide both sides by 6 to cancel the 6 on the left side and make it equal to one:
(6x)/6 = (5 - 18y)/6
1x = (5 - 18y)/6
x = (5 - 18y)/6
6(x + 3y) = 5
6x + 18y = 5
Move 18y to the other side. Don't forget that when moving numbers/variables across the equal sign, we must change the numbers/variables to to opposite sign:
6x = 5 - 18y
Divide both sides by 6 to cancel the 6 on the left side and make it equal to one:
(6x)/6 = (5 - 18y)/6
1x = (5 - 18y)/6
x = (5 - 18y)/6
2009-07-03 1:51 pm
6(x + 3y) = 5
x + 3y = 5/6
x = -3y + 5/6
x + 3y = 5/6
x = -3y + 5/6
2009-07-03 1:22 pm
6 (x + 3y) = 5 <=>
6x + 18y = 5 <=>
6x = 5 - 18y <=>
x = (5 - 18y) / 6
6x + 18y = 5 <=>
6x = 5 - 18y <=>
x = (5 - 18y) / 6
2009-07-03 1:21 pm
First, distribute the 6 through the parenthesis:
6x + 18y = 5
Now, move anything that doesn't have x as a term to the right side of the equation:
6x = 5 - 18y
Now, divide both sides by the coefficient of x:
x = (5 - 18y)/6
6x + 18y = 5
Now, move anything that doesn't have x as a term to the right side of the equation:
6x = 5 - 18y
Now, divide both sides by the coefficient of x:
x = (5 - 18y)/6
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