Find the greatest common factor:
5x^5y^2 + 15x^2y^3 + x^3y^5
(A) xy
(B) x^2y^2
(C) 5xy
(D) 5x^2y^2
Find the greatest common factor: 5x^5y^2 + 15x^2y^3 + x^3y^5 (BEST ANSWER)?
2009-07-02 4:47 pm
回答 (12)
2009-07-02 4:59 pm
✔ 最佳答案
first factorize the terms5x^5y^2= 5 * x * x * x * x * x * y * y
15x^2y^3=3*5 * x * x * y * y * y
x^3y^5= x * x * x * y * y * y * y * y
so the greatest common factor is x*x*y*y
=x^2y^2=B
2009-07-02 4:54 pm
(B)
Just look for the lowest power x and y terms (X^2 and y^2) and the lowest numerical coefficient (1).
Just look for the lowest power x and y terms (X^2 and y^2) and the lowest numerical coefficient (1).
2009-07-02 4:53 pm
it's (B) x^2 y^2
2009-07-02 4:53 pm
your answer is B
x^2y^2( 5x^3+15y+xy^3)
x^2y^2( 5x^3+15y+xy^3)
2016-04-03 10:03 pm
It's 24 because 24*2 = 48 and 24*3 = 72
2009-07-02 4:58 pm
The answer is 100% (B).
2009-07-02 4:56 pm
x^2 y^2
your answer is b
your answer is b
2009-07-02 4:56 pm
5x^5y^2 + 15x^2y^3 + x^3y^5
= x^2y^2(5x^3 + 15y + xy^3)
(answer B)
= x^2y^2(5x^3 + 15y + xy^3)
(answer B)
2009-07-02 4:55 pm
choice b
the greatest common factor (gcf) of 5, 15, and 1 is 1
the gcf of x^5, x^2, and x^3 is x^2
the gcf of y^2, y^3, and y^5 is y^2
so the gcf is 1*x^2*y^2 = x^2y^2 which is choice b
hope that helps
the greatest common factor (gcf) of 5, 15, and 1 is 1
the gcf of x^5, x^2, and x^3 is x^2
the gcf of y^2, y^3, and y^5 is y^2
so the gcf is 1*x^2*y^2 = x^2y^2 which is choice b
hope that helps
2009-07-02 4:51 pm
None of the above are common factors of the equation you gave.
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