would someone help with this math problem?

(x^3 - 27) / (3x^2-8x-3)
= [(x-3)(x^2+3x+9)] / [(3x+1)(x-3)]
= (x^2+3x+9) / (3x+1)

= (x³ - 27)/(3x² - 8x - 3)
= ([x - 3][x² + 3x - 9])/([x - 3][3x + 1])
= (x² + 3x - 9)/(3x + 1)

Answer: (x² + 3x - 9)/(3x + 1)

a^3 - b^3 = (a - b)(a^2 + ab + b^2)

(x^3 - 27)/(3x^2 - 8x - 3)
= (x^3 - 3^3)/(3x^2 + x - 9x - 3)
= [(x - 3)(x^2 + 3x + 9)]/[(3x^2 + x) - (9x + 3)]
= [(x - 3)(x^2 + 3x + 9)]/[x(3x + 1) - 3(3x + 1)]
= [(x - 3)(x^2 + 3x + 9)]/[(3x + 1)(x - 3)]
= (x^2 + 3x + 9)/(3x + 1)

(x-3)(x^2-3x+9)/(3x-5)(x+1/6)

I confirm peter's answer. I got the same thing he did.