Factor by grouping.
4+5xy-10y-2x
Thanks
Can someone help out with this algebra problem?
2009-06-30 3:13 am
回答 (4)
2009-06-30 4:45 am
✔ 最佳答案
4 + 5xy - 10y - 2x= -2x + 4 + 5xy - 10y
= (-2x + 4) + (5xy - 10y)
= -2(x - 2) + 5y(x - 2)
= (x - 2)(-2 + 5y)
= (x - 2)(5y - 2)
2009-06-30 10:19 am
(5xy-10y)+(-2x+4)
5y(x-2)-2(x-2)
(5y-2)(x-2)
5y(x-2)-2(x-2)
(5y-2)(x-2)
2009-06-30 10:19 am
(5xy - 10y) + (4 - 2x)
5y(x - 2) + 2(2 - x)
5y(x - 2) - 2(x - 2)
(5y - 2)(x - 2)
i think
5y(x - 2) + 2(2 - x)
5y(x - 2) - 2(x - 2)
(5y - 2)(x - 2)
i think
2009-06-30 10:17 am
4+5xy-10y-2x =
4 - 2x + 5xy - 10y =
2(2 - x) + 5y(x - 2) =
-2(x - 2) + 5y(x - 2) =
(5y - 2)(x - 2)
4 - 2x + 5xy - 10y =
2(2 - x) + 5y(x - 2) =
-2(x - 2) + 5y(x - 2) =
(5y - 2)(x - 2)
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