solve this in detail 2+9+x=98.?

Hi,I'm a very detailed person,so you can expect a detailed answer from me!!!
(* represents multiplication)

2+9+x=98
2+9=98-x (It becomes negative because when we transfer a positive number beyond the "=" sign it becomes negative,and when we transfer a negative number it becomes positive,and when a number is in a state of multiplication ,it becomes division and if it is in division it becomes multiplication but the sign does not change,for example,if a negative number is in a state of multiplication(or division)and when we transfer it beyond the "=" sign it becomes division(or multiplication if the number before being transferred was in a state of division) but it remains negative,same for positive,if it is positive,it will remain positive and if it is in addition it will change to subtraction after being transferred and if it is in subtraction it will change to addition after being transferred

2+x=98-9
2+x=89
x=89-2
x=87
Answer) x=87
HOPE THIS HELPS.

11 + x = 98
x = 87

CHECK
2 + 9 + 87 = 98 as equired

2 + 9 + x = 98
11 + x = 98
11 + x - 11 = 98 - 11
11 - 11 + x = 87
x = 87

2 + 9 +x = 98 original
11 + x = 98 substitution
11 - 11 + x = 98 - 11 subtraction prop.
x= 87 substitution --

2 + 9 + x = 98
11 + x = 98
x = 98 - 11
x = 87

Proof:
2 + 9 + 87 = 98
98 = 98

2+9= 11 98-11= 87 x=87 ha! esey!

Answering the X
2 plus 9 equals 11 minus 98 equals 87..
the answer to 'x' is 87.

That was awesomely simple

2+9= 11
98-11= 87
x=87

x=98-2-9;
x=87

When you have x^2 = 9, the only thing stopping you from having a solution is that exponent. So to get rid of it and thus isolate x, it makes sense to take the square root of both sides of the equation to get x = ± √9, which means x = 3 or -3. There's nothing wrong with doing it this way or doing it the following way: x^2 = 9 x^2 - 9 = 0 (x+3)(x-3) = 0 x = -3, 3 But again, in the first case you're only one step away. So why not just get rid of the exponent and get the solution. I have to laugh at the person who said to use the quadratic formula. Would somebody REALLY take x^2 = 9, and change it to x^2 - 9 = 0, and THEN plug a=1, b=0, c= -9 into the quadratic formula? It would work, but geez, what a waste of time.