by using quadratic formula
6x^2+5x-3=0
solve equation for x?
2009-06-29 8:57 am
回答 (9)
2009-06-29 9:23 am
✔ 最佳答案
6x^2+5x-3=0a=6 b=5 c=-3
.....-b±√(b^2-4ac)
x=-----------------------
............2a
.....-5±√[(5)^2-4(6)(-3)]
=----------------------------------
...........2(6)
......-5±√[25+72]
=------------------------
............12
......-5±√97
=-----------------
........12
....-5+√97.....-5-√97
x=------------,---------------
......12............12
x=0.404071, -1.237405 answer//
2009-06-29 4:04 pm
Here a = 6, b = 5 and c = - 3
D = 5^2 - 4*6*(-3)
= 25 + 72
= 97
x = [(- 5) + - squareroot 97]/12
D = 5^2 - 4*6*(-3)
= 25 + 72
= 97
x = [(- 5) + - squareroot 97]/12
2009-06-29 8:07 pm
6x^2 + 5x - 3 = 0
x = [-b 屉(b^2 - 4ac)]/(2a)
a = 6
b = 5
c = -3
x = [-5 屉(25 + 72)]/12
x = [-5 屉97]/12
â´ x = [-5 ±â97]/12
x = [-b 屉(b^2 - 4ac)]/(2a)
a = 6
b = 5
c = -3
x = [-5 屉(25 + 72)]/12
x = [-5 屉97]/12
â´ x = [-5 ±â97]/12
2009-06-29 4:26 pm
x = [ - b ± â ( b ² - 4 a c ) ] / 2 a
x = [ - 5 ± â ( 25 + 72 ) ] / 12
x = [ - 5 ± â ( 97 ) ] / 12
x = [ - 5 ± â ( 25 + 72 ) ] / 12
x = [ - 5 ± â ( 97 ) ] / 12
2009-06-29 4:18 pm
the formula is
roots = ( -b +/- sq root ( b*b - 4ac) ) / 2a
when equation is ax^2 + bx + c
which means the answer is
( -5 +/- sq root ( 5*5 - 4*6*-3) ) / 2*6
which will give irrational numbers , ie decimals whose approximate answers are
1.3 & 0.4
roots = ( -b +/- sq root ( b*b - 4ac) ) / 2a
when equation is ax^2 + bx + c
which means the answer is
( -5 +/- sq root ( 5*5 - 4*6*-3) ) / 2*6
which will give irrational numbers , ie decimals whose approximate answers are
1.3 & 0.4
2009-06-29 4:13 pm
6x^2 + 5x - 3 = 0
x = [ -5 +/- (root){ 5^2 - 4(6)(-3) } ]/2(6) it is a formula
x = [ -5 +/- (root){ 25 + 72 } ]/12
x = [ -5 +/- (root){ 97 } ]/12
x = [ -5 +/- 9.849 ]/12
x = 4.849/12 or x = -14.849/12
x =0.404 or x = -1.237
x = [ -5 +/- (root){ 5^2 - 4(6)(-3) } ]/2(6) it is a formula
x = [ -5 +/- (root){ 25 + 72 } ]/12
x = [ -5 +/- (root){ 97 } ]/12
x = [ -5 +/- 9.849 ]/12
x = 4.849/12 or x = -14.849/12
x =0.404 or x = -1.237
2009-06-29 4:12 pm
6x^2+5x-3=0
x= {âb±â(b² â4ac)}/2a
Here a=6 b=5 and c= â3
Hence x ={â5±â(5² â4Ã6Ã( â3))}/(2Ã6)
or x ={â5±â(25+ 72)/12
0r x= {â5±â(97)/12 = 0.404, â1.2374
x= {âb±â(b² â4ac)}/2a
Here a=6 b=5 and c= â3
Hence x ={â5±â(5² â4Ã6Ã( â3))}/(2Ã6)
or x ={â5±â(25+ 72)/12
0r x= {â5±â(97)/12 = 0.404, â1.2374
2009-06-29 4:09 pm
a=6, b=5, c=-3
-b-+(square root)b^2-4ac/2a
-5+-(square root)25+72/12
-5+-9.85/12
either ; or
-5+9.85/12 ; -5-9.85/12
0.40 ; -1.2375
-b-+(square root)b^2-4ac/2a
-5+-(square root)25+72/12
-5+-9.85/12
either ; or
-5+9.85/12 ; -5-9.85/12
0.40 ; -1.2375
2009-06-29 4:00 pm
**** dude, its the summer...
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