solve equation for x?

6x^2+5x-3=0

a=6 b=5 c=-3
.....-b±√(b^2-4ac)
x=-----------------------
............2a

.....-5±√[(5)^2-4(6)(-3)]
=----------------------------------
...........2(6)

......-5±√[25+72]
=------------------------
............12

......-5±√97
=-----------------
........12

....-5+√97.....-5-√97
x=------------,---------------
......12............12

x=0.404071, -1.237405 answer//

Here a = 6, b = 5 and c = - 3
D = 5^2 - 4*6*(-3)
= 25 + 72
= 97
x = [(- 5) + - squareroot 97]/12

6x^2 + 5x - 3 = 0
x = [-b ±√(b^2 - 4ac)]/(2a)

a = 6
b = 5
c = -3

x = [-5 ±√(25 + 72)]/12
x = [-5 ±√97]/12

∴ x = [-5 ±√97]/12

x = [ - b ± √ ( b ² - 4 a c ) ] / 2 a

x = [ - 5 ± √ ( 25 + 72 ) ] / 12

x = [ - 5 ± √ ( 97 ) ] / 12

the formula is

roots = ( -b +/- sq root ( b*b - 4ac) ) / 2a

when equation is ax^2 + bx + c

which means the answer is

( -5 +/- sq root ( 5*5 - 4*6*-3) ) / 2*6

which will give irrational numbers , ie decimals whose approximate answers are

1.3 & 0.4

6x^2 + 5x - 3 = 0

x = [ -5 +/- (root){ 5^2 - 4(6)(-3) } ]/2(6) it is a formula
x = [ -5 +/- (root){ 25 + 72 } ]/12
x = [ -5 +/- (root){ 97 } ]/12
x = [ -5 +/- 9.849 ]/12
x = 4.849/12 or x = -14.849/12
x =0.404 or x = -1.237

6x^2+5x-3=0
x= {−b±√(b² −4ac)}/2a
Here a=6 b=5 and c= −3
Hence x ={−5±√(5² −4×6×( −3))}/(2×6)
or x ={−5±√(25+ 72)/12
0r x= {−5±√(97)/12 = 0.404, −1.2374

a=6, b=5, c=-3

-b-+(square root)b^2-4ac/2a

-5+-(square root)25+72/12
-5+-9.85/12
either ; or
-5+9.85/12 ; -5-9.85/12
0.40 ; -1.2375

**** dude, its the summer...