A man died and left a will. He had 3 sons and 17 camels. Figure out how many camels will each son get?

👨🏻‍🏫 學術台數學

[匿名]

2009-06-27 1:48 pm

In his will he gave 1/2 of his camels to his 1st son, 1/3 to his 2nd son and 1/9 to his 3rd son. How many camels will each son gets?

更新1:

Hi Jackie n :-D you did not try hard enough. See how others could get the answer.

更新2:

Thats my point you need to add 1 camel.

更新3:

This is a true story. There was no algebra then. Infact even those who already knew the answer, i believe adding one camel to the 17 is trully genius. Thanks everyone for taking part.

回答 (12)

[匿名]

2009-06-27 1:54 pm

✔ 最佳答案

you cannot split a camel in half .. half of 17 is 8.5... unless another camel is added by the judge then which son gives back the camel after huh?

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[匿名]

2009-06-27 8:54 pm

Omar lends the estate one camel.

Therefore, 1st son gets 9

2nd son gets 6

3rd son gets 2

Omar gets his camel back !

QED

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[匿名]

2009-06-27 9:01 pm

(1 / 2)x + (1 / 3)x + (1 / 9)x = 1
9x + 6x + 2x = 18
17x = 18
x = 1

therefore, 1st son gets 9; 2nd son gets 6; 3rd son gets 2.

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[匿名]

2009-06-28 5:39 am

8.5, 5.6666666..., 1.6666666...
So Rounded 9, 6, 2
But Physically Impossible :)

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[匿名]

2009-06-27 9:25 pm

the first son = 9
the second son= 6
the third son= 2

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[匿名]

2009-06-27 8:58 pm

is this old chestnut still going around?.
Borrow a camel from mustapha phag and it is very easy then

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nozar nazari

2009-06-27 8:58 pm

The glourious gentleman had a note,asked them to get one more camel,then 18/2 + 18/3 + 18/9=17,
then returned the one.

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maussy

2009-06-27 8:55 pm

A old story. The judge who made the deal add 1 camel to the herd. So ,there was 18 camels
the elder received 18/2=9 camels
the second 18/2=6 camels
the youngest 18/9=2 camels

and the judge took his camel again

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[匿名]

2009-06-27 9:04 pm

the first son 10 camels
the second son 5 camels
the third 2 son

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[匿名]

2009-06-27 8:53 pm

I guess its 9 for first son,5 for second and 3 for third....

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