How do i solve 3x^2+8x=-4?
回答 (8)
2009-06-27 9:51 am
✔ 最佳答案
3x^2 + 8x = -43x^2 + 8x + 4 = 0
3x^2 + 6x + 2x + 4 = 0
(3x^2 + 6x) + (2x + 4) = 0
3x(x + 2) + 2(x + 2) = 0
(x + 2)(3x + 2) = 0
x + 2 = 0
x = -2
3x + 2 = 0
3x = -2
x = -2/3
Hence, x = -2 or -2/3.
2009-06-27 3:08 pm
x=-2 or x = - 2 / 3
2009-06-27 10:53 am
3 x ² + 8 x + 4 = 0
( 3 x + 2 ) ( x + 2 ) = 0
x = - 2 / 3 , x = - 2
( 3 x + 2 ) ( x + 2 ) = 0
x = - 2 / 3 , x = - 2
2009-06-27 10:09 am
3x^2+8x=-4
3x^2+8x+4=0
(3x+2)(x+2)=0
3x+2=0 x+2=0
3x=-2 x=-2
x=-2/3
x={-2/3,-2} answer//
3x^2+8x+4=0
(3x+2)(x+2)=0
3x+2=0 x+2=0
3x=-2 x=-2
x=-2/3
x={-2/3,-2} answer//
2009-06-27 10:03 am
3x^2+8x+4=0
x=[-4+&-(16-12)^1/2]/3=-2/3 & -3
x=[-4+&-(16-12)^1/2]/3=-2/3 & -3
2009-06-27 9:51 am
3x^2+8x+4=0
(x+ 2/3)(x+2)=0
x=-2 x=-2/3
(x+ 2/3)(x+2)=0
x=-2 x=-2/3
2009-06-27 9:51 am
3x^2+8x=-4
3x^2+8x+4=0
(3x+2)(x+2)=0
x = -2/3 or -2
3x^2+8x+4=0
(3x+2)(x+2)=0
x = -2/3 or -2
2009-06-27 9:49 am
Hi,
3x² + 8x = -4
3x² + 8x + 4 = 0
(3x + 2)(x + 2) = 0
So, x = -2/3 or -2
Hope this helps!
3x² + 8x = -4
3x² + 8x + 4 = 0
(3x + 2)(x + 2) = 0
So, x = -2/3 or -2
Hope this helps!
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