問數學log 的問題

2009-06-27 11:32 pm
不等式 log2/1 (2X-3)>log2/1(X+1)之解為

回答 (2)

2009-06-27 11:59 pm
✔ 最佳答案
log1/2 (2X-3)>log1/2(X+1)
log (2x-3)/log(1/2)>log(x+1)/log(1/2)
log (2x-3)<log(x+1) [因 log(1/2) < 0 ]
(2x-3)<(x+1) [ 因 log 單調上升 ]
x<4
2009-06-27 11:47 pm
log2/1 (2X-3) 即是底數為2/1??


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