give that log5=0.699 and log3=0.477 find log45 without using mathematical table or calculator.hence solve x^0.?

2009-06-23 10:36 am

回答 (5)

2009-06-23 11:07 am

✔ 最佳答案

log(45) = log(5 * 3^2)= log(5) + 2 * log(3)
=1.653

x^0 = x^(3-3)
=log(3-3)
=log(3)/log(3)
=0.477/0.477
=1

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2009-06-23 5:43 pm

log(a * b) = log(a) + log(b)

log(45) = log(5 * 3^2) = log(5) + log(3^2) = log(5) + 2 * log(3)

.699 + .954 = 1.653

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2009-06-23 7:29 pm

log(5) = 0.699
log(3) = 0.477

log(45)
= log(3 * 3 * 5)
= log(3) + log(3) + log(5)
= 0.477 + 0.477 + 0.699
= 1.653

x^0 = 1

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2009-06-23 6:09 pm

log 45
log ( 5 x 9 )
log ( 5 x 3 Â² )
log 5 + 2 log 3
0.699 + 0.477
1.176

x^0 = 1

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2009-06-23 5:44 pm

log9 = log(3^2) = 2log3
log45 = log(5*9) = log5+log9 = log5+2log3

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