小四題直角等腰三角形 , 求它的等腰長和面積 , 唔該

169cm^2
169cm^2

你是不是想說直角等腰三角形的斜邊是26cm?

Let x cm be the base and the height of the isos. triangle

x^2+x^2=26^2 (Pyth.Theorem)

2(x^2)=676

x^2=338

x=18.38477631

i.e.The height and the base of the isos. triangle is 18.4cm (cor.to 3sig.fig.)

Area of the isos. triangle=
(18.38477631X18.38477631)/2
= 338/2
=169cm^2
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如果依你所說三角形的底是26cm ,
那麼它的等腰長也是26cm

Area of the triangle=
(26X26)/2
=676/2
=338 cm^2