[不恥下問系列]又有GMAT數學題不懂之17

2009-06-23 5:08 am
Two water pumps, working simultaneously at their respective constant rates, took exactlyu 4 hours to fill a certain swimming pool. If the constant rate of one pump was 1.5 times the constant rate of the other, how many hours would it have taken the faster pump to fill the pool if it had worked alone at its constant rate?

a) 5
b) 16/3
c) 11/2
d) 6
e) 20/3

THX!

回答 (3)

2009-06-23 5:22 am
✔ 最佳答案
Assume :
the volume of the pool is V m^3
the constant rate of pump A be x m^3/h
then the constant rate of pump B be 1.5x m^3/h
Since :
Two water pumps, working simultaneously at their respective constant rates, took exactlyu 4 hours to fill a certain swimming pool
By time=volume/rate
4=V/(1.5x+x)
V/x=10
The time reqired for the faster pump to fill the pool if it had worked alone at its constant rate
=V/(1.5x)
=(1/1.5)(V/x)
=(10/1.5)
=20/3 hour
Ans :E
2009-06-23 5:53 am
let x be the rate of the slower pump

rate of faster pump = 1.5x

volume of the pool = (1.5x + x) * 4 hrs = 10x

time required to fill up the pool with faster pump

= 10x / 1.5x = 20 / 3

answer = E
2009-06-23 5:17 am
1/[(1/x+1/(1.5x)]=4
3x/(3+2)=4
3x=20
x=20/3
(c)



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