The coefficient of friction of an inclined plane is tan a. If a wooden block of mass m is placed on the inclined plane which is at an angle b ( b < a ).
Will the wooden block slide ? If not, what forces are keeping the block at rest on the inclined plane and what is their magnitude and direction.
Inclined Plane
2009-06-22 5:14 am
回答 (2)
2009-06-22 10:02 pm
✔ 最佳答案
The answer is as follows:圖片參考：http://i320.photobucket.com/albums/nn347/old-master/090622_1.jpg?t=1245650488
2009-06-22 4:28 pm
The block will not slide.
The forces keeping it at rest are normal reaction (N) by the plane (normal to the plane and upwards) and the friction force (f) by the plane also (downwards the plane).
By considering the components of the weight along the plane and the normal to the plane
N = mgcos(b)
f = mg sin(b) < mgsin(a) (which is the maximum friction on the plane,so it doesn't move)
The forces keeping it at rest are normal reaction (N) by the plane (normal to the plane and upwards) and the friction force (f) by the plane also (downwards the plane).
By considering the components of the weight along the plane and the normal to the plane
N = mgcos(b)
f = mg sin(b) < mgsin(a) (which is the maximum friction on the plane,so it doesn't move)
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