Solve for x..please help?
回答 (9)
2009-06-20 4:32 pm
✔ 最佳答案
x-7.....5.......x+9----- - ---- = --------- lcd:10
..5......2.......10
2(x-7)-25=x+9
2x-14-25=x+9
2x-39=x+9
2x-x=39+9
x=48 answer//
2009-06-23 8:22 pm
2 x - 14 - 25 = x + 9
x - 39 = 9
x = 48
x - 39 = 9
x = 48
2009-06-21 12:21 am
(x - 7)/5 - 5/2 = (x + 9)/10
(x - 7)/5 - (x + 9)/10 = 5/2
(2/2)[(x - 7)/5] - (x + 9)/10 = 5/2
[2(x - 7)]/10 - (x + 9)/10 = 5/2
(2*x - 2*7)/10 - (x + 9)/10 = 5/2
(2x - 14 - x - 9)/10 = 5/2
(2x - x - 14 - 9)/10 = 5/2
(x - 23)/10 = 5/2
x - 23 = 10(5/2)
x - 23 = 25
x = 25 + 23
x = 48
(x - 7)/5 - (x + 9)/10 = 5/2
(2/2)[(x - 7)/5] - (x + 9)/10 = 5/2
[2(x - 7)]/10 - (x + 9)/10 = 5/2
(2*x - 2*7)/10 - (x + 9)/10 = 5/2
(2x - 14 - x - 9)/10 = 5/2
(2x - x - 14 - 9)/10 = 5/2
(x - 23)/10 = 5/2
x - 23 = 10(5/2)
x - 23 = 25
x = 25 + 23
x = 48
2009-06-20 11:33 pm
it's easiest to just multiply each term by 10.
you get 2(x-7) -25 = x + 9
then distribute...2x-14-25=x + 9
collect terms....x=48
you get 2(x-7) -25 = x + 9
then distribute...2x-14-25=x + 9
collect terms....x=48
2009-06-20 11:31 pm
x – 7)/5 – 5/2 = (x + 9)/10
{2(x-7) -5(5)} / 5(2) =(x+9)/10
{2(x-7) -5(5)} / 10 =(x+9)/10
denominators get cancelled
2(x-7) -5(5) =(x+9)
2x-14 -25 =x+9
2x-39=x+9
2x-39-x-9=0
x-48=0
x=48
{2(x-7) -5(5)} / 5(2) =(x+9)/10
{2(x-7) -5(5)} / 10 =(x+9)/10
denominators get cancelled
2(x-7) -5(5) =(x+9)
2x-14 -25 =x+9
2x-39=x+9
2x-39-x-9=0
x-48=0
x=48
2009-06-20 11:31 pm
the Equation becomes: ( (x-7)2 - 25 ) / 10 = ( x+9) / 10
( 2x - 39 ) / 10 = (x+9)/10
Multiply both by 10 and 2x - 39 = x + 9
x = 39 + 9 = 48 =)
( 2x - 39 ) / 10 = (x+9)/10
Multiply both by 10 and 2x - 39 = x + 9
x = 39 + 9 = 48 =)
參考: The Pen and paper i found in front on me =)
2009-06-20 11:28 pm
(x – 7)/5 – 5/2 = (x + 9)/10
{2(x-7) -5(5)} / 5(2) =(x+9)/10
{2(x-7) -5(5)} / 10 =(x+9)/10
denominators get cancelled
2(x-7) -5(5) =(x+9)
2x-14 -25 =x+9
2x-39=x+9
2x-39-x-9=0
x-48=0
x=48
{2(x-7) -5(5)} / 5(2) =(x+9)/10
{2(x-7) -5(5)} / 10 =(x+9)/10
denominators get cancelled
2(x-7) -5(5) =(x+9)
2x-14 -25 =x+9
2x-39=x+9
2x-39-x-9=0
x-48=0
x=48
2009-06-20 11:26 pm
First try multiplying both sides by 5. You get x-7-25/2 = x+9/2. Multiply both sides by 2 and you get 2x-14-25= x+9. Subtract x from both sides you get x-39=9. Add 39 to both sides you get x=48.
2009-06-20 11:24 pm
(x – 7)/5 – 5/2 = (x + 9)/10
multiply both sides by 10 to clear the denominators
2(x-7) - 10 = x + 9
do the indicated multiplication
2x - 14 - 10 = x + 9
subtract x from both sides and do indicated arithmetic
x - 24 = 9
add 24 to both sides
x = 33
multiply both sides by 10 to clear the denominators
2(x-7) - 10 = x + 9
do the indicated multiplication
2x - 14 - 10 = x + 9
subtract x from both sides and do indicated arithmetic
x - 24 = 9
add 24 to both sides
x = 33
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