(1/2)(5x - 1) - (2/3)(4x - 2)?

2009-06-20 4:01 pm
Apply the distributive property to simplify; then combine all like terms:

回答 (5)

2009-06-20 4:41 pm
✔ 最佳答案
(1/2)(5x - 1) - (2/3)(4x - 2)
= (5x - 1)/2 - [2(4x - 2)]/3
= (3/3)[(5x - 1)/2] - (2/2)[(2*4x - 2*2)]/3]
= [3(5x - 1)]/6 - [2(8x - 4)]/6
= (3*5x - 3*1)/6 - (2*8x - 2*4)/6
= (15x - 3)/6 - (16x - 8)/6
= (15x - 3 - 16x + 8)/6
= (15x - 16x - 3 + 8)/6
= (-x + 5)/6
2016-12-15 3:59 am
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2009-06-20 4:25 pm
(1/2)(5x - 1) - (2/3)(4x - 2)

5x/2-1/2-8x/3+4/3
=-1/6x+5/6
2009-06-20 4:19 pm
(1/2)(5x - 1) - (2/3)(4x - 2)?

You have an indicated distribution of 1/2 across (5x - 1).
So
It means multiply the whole thing by 1 and divide the whole thing by 2
1 times (5x -1) equals (5x - 1)

dividing looks like this
(5x - 1) / 2
or
5x/2 - 1/2

Use the same approach for the second part
(2/3)(4x - 2) = (8x - 4) / 3
but there was a minus in front of this, so we have
- (8x - 4)/3
which equals
-8x/3 + 4/3

Now to combine like terms
5x/2 - 1/2 - 8x/3 + 4/3
the terms containing x are "like terms"
5x/2 - 8x/3
and the terms without unknowns are "like terms"
4/3 - 1/2
but we need common denominators
you can handle that, right?
2009-06-20 4:09 pm
change all denominators to 6 after multiplying it out...
5/2x - 3/6 -16/6x + 8/6=
-1/6x + 5/6


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