x^2 +y^2 -2x -10y +25 = 0
plz , show all the steps clearly
更新1:
y = 0 is impossible anwser because this line is not touching the circumference of the circle do you have any other anwser?
a maths
2009-06-21 3:24 am
find the equation of tangent from the point A( 0 , 5 ) to the circle
x^2 +y^2 -2x -10y +25 = 0
plz , show all the steps clearly
x^2 +y^2 -2x -10y +25 = 0
plz , show all the steps clearly
回答 (3)
2009-06-21 3:41 am
✔ 最佳答案
centre of circle=(1,5) radius of circle=√(12+52-25)
=1
∴The equation of tangent is y=0.
2009-06-20 20:15:39 補充：
∴The equation of tangent is x=0.
2009-06-21 7:18 pm
centre of circle is (1,5)
radius= 1
tangent ofcircle is y-5-Mx=0
absolute value ( y-5-Mx /(1+M^2)^0.5 )=1
put y=5,x=1
absolute value ( 5-5-M /(1+M^2)^0.5 )=1
M^2=1+M^2
1=0
tangent is x=0
radius= 1
tangent ofcircle is y-5-Mx=0
absolute value ( y-5-Mx /(1+M^2)^0.5 )=1
put y=5,x=1
absolute value ( 5-5-M /(1+M^2)^0.5 )=1
M^2=1+M^2
1=0
tangent is x=0
參考: me
2009-06-21 3:58 am
x=0?
收錄日期: 2021-04-23 23:18:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090620000051KK01612