log6(3x + 15) = 3, then x =?

3x + 15 = 6^3 = 216
3x = 201
x = 67

3 x + 15 = 6 ³

3 x + 15 = 216

3 x = 201

x = 67

rewrite in exponential form

6 ^ 3 = (3x + 15)

216 = 3x + 15......subtract 15

201 = 3x.....divide by 3

67 = x <----------solution

hope this helps !

(3x + 15) = 6^3
(x+5) = 72
x = 67

log[6] (3x + 15) = 3
3x + 15 = 6^3 = 216
3x = 201
x = 67

x = 67

u know
if log b to the base a= n, then b= a^n
given log(3x+15)to base6 = 3
here a=6, n=3 and b=3x+15
so 3x+15 = 6³
3x=6³-15, x= 201/3=67

log_6(3x + 15) = 3
3x + 15 = 6^3
3x + 15 = 216
3x = 216 - 15
x = 201/3
x = 67

3x+15=216
3x=201
x=67

Most of the answers which get the x value as 67 are correct.