log6(3x + 15) = 3, then x =?
回答 (12)
2009-06-19 10:48 am
✔ 最佳答案
3x + 15 = 6^3 = 2163x = 201
x = 67
2009-06-19 2:16 pm
3 x + 15 = 6 ³
3 x + 15 = 216
3 x = 201
x = 67
3 x + 15 = 216
3 x = 201
x = 67
2009-06-19 2:17 pm
rewrite in exponential form
6 ^ 3 = (3x + 15)
216 = 3x + 15......subtract 15
201 = 3x.....divide by 3
67 = x <----------solution
hope this helps !
6 ^ 3 = (3x + 15)
216 = 3x + 15......subtract 15
201 = 3x.....divide by 3
67 = x <----------solution
hope this helps !
2009-06-19 2:17 pm
(3x + 15) = 6^3
(x+5) = 72
x = 67
(x+5) = 72
x = 67
2009-06-19 2:16 pm
log[6] (3x + 15) = 3
3x + 15 = 6^3 = 216
3x = 201
x = 67
3x + 15 = 6^3 = 216
3x = 201
x = 67
2009-06-21 12:04 pm
x = 67
2009-06-20 8:04 pm
u know
if log b to the base a= n, then b= a^n
given log(3x+15)to base6 = 3
here a=6, n=3 and b=3x+15
so 3x+15 = 6³
3x=6³-15, x= 201/3=67
if log b to the base a= n, then b= a^n
given log(3x+15)to base6 = 3
here a=6, n=3 and b=3x+15
so 3x+15 = 6³
3x=6³-15, x= 201/3=67
2009-06-19 3:26 pm
log_6(3x + 15) = 3
3x + 15 = 6^3
3x + 15 = 216
3x = 216 - 15
x = 201/3
x = 67
3x + 15 = 6^3
3x + 15 = 216
3x = 216 - 15
x = 201/3
x = 67
2009-06-19 2:47 pm
3x+15=216
3x=201
x=67
3x=201
x=67
2009-06-19 2:24 pm
Most of the answers which get the x value as 67 are correct.
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