simplify 4x^2+8x+4 for me?

(pull out 4)

4 ( x^2 + 2x + 1 )

(factor right side)

4 ( x + 1 ) ( x + 1 )

4 ( x + 1 )^2

= 4x² + 8x + 4
= 4(x² + 2x + 2)
= 4(x + 1)(x + 1)

Answer: 4(x + 1)(x + 1) OR 4(x + 1)²

4 ( x ² + 2 x + 1 )

4 ( x + 1 ) ( x + 1 )

4 ( x + 1 ) ²

4x^2+ 8x + 4 = 4(x^2 + 2x + 1) = 4(x + 1)²

12x^2+4

4x^2 + 8x + 4
= 4(x^2 + 2x + 1)
= 4(x^2 + x + x + 1)
= 4[(x^2 + x) + (x + 1)]
= 4[x(x + 1) + 1(x + 1)]
= 4(x + 1)(x + 1)
= 4(x + 1)^2

4x^2+8x+4
4x^2+4x+4x+4
4x(x+1)+4(x+1)
(4x+4)(x+1)

= 4x^2 + 4x + 4x +4
= 4x(x+1) + 4(x+1)
=4(x+1)(x+1)
4(x+1)^2

this is the middle term method in which u have 2 use this way:
the equation is 4x^2+8x+4 ...that is ax^2 + bx +c
here a=4....b=8....c=4
now mutiply a and c.... u get 16
now u have to think about all the factors that make sixteen..e.g. 4x4=16...2x8=16
and do sth with these factors to make b ..which is 8
so 4 +4= 8
that's y i broke 8 into 4 and 4

(2X+2)^2